Calculate the volume of 7.0M NaOH required to prepare 300. mL of 0.50M NaOH.

Question

Question

Answer 1

Answer #1

We will solve it by dilution equation M1V1= M2V2

M1= initial concentration = 7 M V1= initial volume =?

M2= final concentration = 0.50 M V2= final volume = 300 mL

V1 = M2V2/M1= 0.50*300/7 =21.43 mL

Answer 2

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