Question

Write a complete program in assembly line that:
   1. Prompt the user to enter 10 numbers.
   2. save those numbers in a 32-bit integer array.
   3. Print the array with the same order it was entered.
   3. Calculate the sum of the numbers and display it.
   4. Calculate the mean of the array and display it.
   5. Rotate the members in the array forward one position for
       9 times. so the last rotation will display the array in reversed order.
    6. Print the array after each rotation.
       check the sample run.
------------------------------------------------------------
      Don't use any shift or rotate instructions. You need to use loops and indexed addressing.
      All you work should be on the original array. Don't make
      a copy of the array at any time.

Answer 1

#include <iostream>

using namespace std;

int main() {

             

              int arr[10];

              for (int i=1;i<=10;i++){    //________________ taking input

                             cout<<"Enter "<<i<<" Element : ";

                             cin >>arr[i-1];

              }

              cout<<"\n"<<"Array created : "<<"\n";

              for (int i = 0;i<10;i++){

                             cout<<arr[i]<<" ";

              }

              int sum=0;

              for (int i = 0;i<10;i++){    //________________calculating sum

                             sum+=arr[i];

              }

              float mean=(float)sum/10;

              cout<<"\n\n"<<"sum : "<<sum<<"    mean "<<mean<<"\n";

              int count=1;

              int tmp;

              int index = 0;

              while(count<=9){            //______________rotating the array

tmp = arr[9];

for(int i=9;i>index;i--){

                             arr[i]=arr[i-1];

}

arr[index]=tmp;

index++;

cout<<"\n"<<"After "<<count<<" rotation :"<<"\n";

for(int i=0;i<10;i++){

                             cout<<arr[i]<<" ";

}

count++;

              }

              return 0;

}