Convert 15 ppb of Lead (Pb) to mg/kg. Show work.
The EPA limits lead to 15 ppb. What mass of lead (in micrograms) is there in an 8oz glass of water that contains 15 ppb of lead?
The maximum amount of lead allowed in drinking water is 0.015 mg/kg of water. Express this amount in ppb. TT T Arial 3 (12pt) T-SE
Flint, Michigan faces a serious water contamination crisis with high levels of lead (Pb) found in the water. The EPA has a limit of 0.015 mg/L. Express this concentration in units of ppb. Assume the water has a density of 1 g/mL.
show work neatly please Show your work for credit. 1. Convert a) 469.82 ng to mg b) 41.0 mL to μL c) 318 ft to cm d) How many cm3 are there in 1.25 ft3?
A magnesium-lead alloy of mass 9.7 kg consists of a solid α phase that has a composition just slightly below the solubility limit at 300°C (570°F). The magnesium-lead phase diagram is shown in Animated Figure 10.20. (a) What mass of lead is in the alloy? kg (b) If the alloy is heated to 400°C (750°F), how much more lead may be dissolved in the α phase without exceeding the solubility limit of this phase? wt%Pb = (m_Pb + m_add /...
Unit conversion. (10 pts) Convert a concentration of 5.62 ´1013 molecules/cm 3 to the ppb scale. Assume 25° C and 1.0 atm total air pressure. Convert a concentration of 6.0 ´1014 molecules/cm 3 to the moles per liter (molarity) scale. Assume 27.5° C and 0.99 atm total air pressure. Convert a concentration of 36.5 ppb of ozone, O3, into the number of molecules/cm3. Assume the air mass temperature is 25.3° C and its total pressure is 1.05 atm. Convert a...
2. Convert the value to the specified unit (you must show all work for credit). a. 1245 kg to mg 1249 kg x 1000000 = 1 kg = 1000000 = 1 mg 124G000000 mg 2000000 ang mund o b. 122.355 s to ks 122.355 x (1 ks/1000 s) = 0,122355 KS C. 544 m/s to uK/ms 554 3. Convert 15.0L to m3
Please show all work Ex: convert a) 670 ng to Mg b) c) d) e) 78nm3 to L Convert 864mg/CL to μg/ML 674 mm3 to gallons (1 gal=3.785L) Convert 467 Tm to miles. 1 mi-1.609 km.
Convert the units. 29 kg = mg O A. 0.029 mg O B. 29,000,000 mg O c. 2,900 mg D. 0.29 mg
For each of the following provide: i) The phases present ii) The composition of each phase iii) The relative wt% of each phase a) 15 wt% Sn-85 wt% Pb at 100°C b) 1.25 kg Sn and 1.4 kg Pb at 200oC c) 55 wt% Zn-45 wt% Cu at 600 °C d) 1.88 kg Cu and 2.12 kg Zn at 500°C e) 21.7 mol Mg and 35.4 mol Pb at 350°C For each of the following provide: i) The phases present...