How many fissions take place per second in a 190-MW reactor? Assume 200 MeV is released...
How many fissions take place per second in a 190-MW reactor? Assume 200 MeV is released per fission.
Homework Answers
First let's see how many Mev we need to equal 190 megawatts, or 1.9 * 10^8
watts, or joules per second. One watt equals 1 joule (1
volt-coulomb) per sec.
Since 1 coulomb = 6.28 * 10^18 electrons, 1 joule = 6.28 * 10^18
eV.
So 190 megawatts = (1.9 * 10^8)(6.28 * 10^18) = 11.932 * 10^26 eV
per sec.
If each fission produces 200 MeV or 2.0 * 10^8 eV, we need:
(11.932 * 10^26) / (2.0 * 10^8) = 5.966 * 10^18 fissions per
second.
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When 235U fissions, the fission products are not always the same and exactly two neutrons are...
When 235U fissions, the fission products are not
always the same and exactly two neutrons are not always released.
An example of one fission reaction is
You may want to use the following table of atomic masses:
Table of masses
141Ba
140.9144 u
144Ba
143.9229 u
139Te
138.9347 u
141Cs
140.9196 u
90Kr
89.91952 u
91Kr
90.92344 u
92Kr
91.92615 u
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93Rb
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235U
235.0439 u
p
1.00728 u
n
1.00867 u
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always the same and exactly two neutrons are not always released.
An example of one fission reaction is
You may want to use the following table of atomic masses:
Table of masses
141Ba
140.9144 u
144Ba
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139Te
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141Cs
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90Kr
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91Kr
90.92344 u
92Kr
91.92615 u
94Zr
93.90632 u
93Rb
92.92157 u
235U
235.0439 u
p
1.00728 u
n
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