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The demand for a product is normally distributed with an average daily demand of 90 units...

The demand for a product is normally distributed with an average daily demand of 90 units and a standard deviation of 20. The lead time for the component is 4 days. A service level of 97.5% is desired. What is the optimal re-order point? ANSWER IS 438 UNITS. Please show steps as I do not know how they got here.

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Answer #1

Average daily demand (d) = 90 units

Lead time (L) = 4 days

The standard deviation of daily demand (d) = 20 units

Service level expectancy = 97.5%

Z-value corresponding to 97.5% service level = 1.96

Ans A)

Re-order point (R) is given by the formula,

units

Hence, rounding down, the re-order point is 438 units.

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