n | x | p | |||
---|---|---|---|---|---|
0.10 | 0.15 | 0.20 | 0.25 | ||
18 | 0 | 0.1501 | 0.0536 | 0.0180 | 0.0056 |
1 | 0.3002 | 0.1704 | 0.0811 | 0.0338 | |
2 | 0.2835 | 0.2556 | 0.1723 | 0.0958 | |
3 | 0.1680 | 0.2406 | 0.2297 | 0.1704 | |
4 | 0.0700 | 0.1592 | 0.2153 | 0.2130 | |
5 | 0.0218 | 0.0787 | 0.1507 | 0.198 |
It was determined that the probability that 2 or fewer students withdraw from the course will be the sum of these events.
Using the table, we found f(0) = 0.0536, f(1) = 0.1704, and f(2) = 0.2556. Find this probability to four decimal places.
probability of 2 or fewer students withdraw | = | f(0) + f(1) + f(2) |
= | 0.0536 + + 0.2556 | |
= |
n = 18
p = 0.10 0.15 0.20 0.25
0 | 0.1501 | 0.0536 | 0.0180 | 0.0056 | |
1 | 0.3002 | 0.1704 | 0.0811 | 0.0338 | |
2 | 0.2835 | 0.2556 | 0.1723 | 0.0958 | |
3 | 0.1680 | 0.2406 | 0.2297 | 0.1704 | |
4 | 0.0700 | 0.1592 | 0.2153 | 0.2130 | |
5 | 0.0218 | 0.0787 | 0.1507 | 0.198 |
When p = 0.15, f(0) = 0.0536, f(1) = 0.1704, and f(2) = 0.2556.
Probability that 2 or fewer students withdraw from the course
= f(0) + f(1) + f(2)
= 0.0536 + 0.1704 + 0.2556
= 0.4796
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