Question

n x p 0.10 0.15 0.20 0.25 18 0 0.1501 0.0536 0.0180 0.0056 1 0.3002 0.1704...

n x p
0.10 0.15 0.20 0.25
18 0 0.1501 0.0536 0.0180 0.0056
1 0.3002 0.1704 0.0811 0.0338
2 0.2835 0.2556 0.1723 0.0958
3 0.1680 0.2406 0.2297 0.1704
4 0.0700 0.1592 0.2153 0.2130
5 0.0218 0.0787 0.1507 0.198

It was determined that the probability that 2 or fewer students withdraw from the course will be the sum of these events.

Using the table, we found f(0) = 0.0536, f(1) = 0.1704, and f(2) = 0.2556. Find this probability to four decimal places.

probability of 2 or fewer students withdraw = f(0) + f(1) + f(2)
= 0.0536 +  + 0.2556
=
0 0
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Answer #1

n = 18

p = 0.10 0.15 0.20 0.25

0 0.1501 0.0536 0.0180 0.0056
1 0.3002 0.1704 0.0811 0.0338
2 0.2835 0.2556 0.1723 0.0958
3 0.1680 0.2406 0.2297 0.1704
4 0.0700 0.1592 0.2153 0.2130
5 0.0218 0.0787 0.1507 0.198

When p = 0.15, f(0) = 0.0536, f(1) = 0.1704, and f(2) = 0.2556.

Probability that 2 or fewer students withdraw from the course

= f(0) + f(1) + f(2)

= 0.0536 + 0.1704 + 0.2556

= 0.4796

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