How many discs of one-inch diameter can you fit in a rectangle of size 5 inches by 3.6 inches? (In a sense, the capacity of the rectangle with respect to the discs)
(This is a two-dimensional problem - you cannot stack discs)
Total = 5+4+5+4 = 18
Arrangement will be like:
Area of disc = pi*((d/2)^2 = 3.14*(0.5)^2 = 0.785
Area of rectangle = l*b = 5*3.6 = 18
Maximum Number of disc possible = Area of rectangle/Area of disc = 18/0.785 = 22.9
So, 18 is possible basis hit and trial
How many discs of one-inch diameter can you fit in a rectangle of size 5 inches...
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