Question

Write a function called expensiveBooks which receives a double array of book prices and the number of books.

Return the total number of books that are priced over 100.0.

Answer 1

FUNCTION

int expensiveBooks(double *price,double *nob)
{
    int count=0;
    int i;
    for(i=0;i<n;i++)
    {
       if(*(price+i)>100)
       count =count +*(nob+i);
   }
   return count;
}

PROGRAM

#include<iostream>
#include<iomanip>
using namespace std;
int n;
//method to count the number of books that are greater than 100 price
int expensiveBooks(double *price,double *nob)
{
    int count=0;
    int i;
    for(i=0;i<n;i++)
    {
       if(*(price+i)>100)
       count =count +*(nob+i);
   }
   return count;
}
//driver program
int main()
{
   int i;
   //ask for numbe of data you want to enter
   cout<<endl<<"Enter the number of data ";
   cin>>n;
   //allocate the size of array
   double *price = new double[n];
   double *nob = new double[n];
   //input the prices for books
   cout<<endl<<"Enter the prices for "<<n<<" number of books";
   for(i=0;i<n;i++)
   cin>>*(price+i);
   //enter the number of copies
   cout<<endl<<"Enter the number of books for "<<n<<" books";
   for(i=0;i<n;i++)
   cin>>*(nob+i);
   //display the book details
   cout<<endl<<"Book Details"<<endl;
   cout<<endl<<"Number of Books Price of Books"<<endl;
   for(i=0;i<n;i++)
   cout<<endl<<" "<<*(nob+i)<<"\t\t\t"<<*(price+i);
   //display the result
   i=expensiveBooks(price,nob);
   cout<<endl<<" There are "<<i<<" Number of books above price 100.00";
     
}

OUTPUT