Question

Wiley Coyote has missed the elusive road runner once again. This time, he leaves the edge of the cliff at 52.4 m/s horizontal velocity. If the canyon is 140 m deep, how far from his starting point at the edge of the cliff does the coyote land?

Answer 1

Initial horizontal velocity,

Initial vertical velocity,

Height of the canyon,

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First, find the time of flight

Consider the vertical motion of Wiley Coyote

Use formula

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Consider the horizontal motion of Wiley Coyote

There is no acceleration in horizontal direction, so horizontal velocity remains a constant.

Horizontal velocity = Horizontal distance/Time of flight

ANSWER:

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