Wile E. Coyote is standing at the top of a 300 m cliff. Road Runner startles him, and he falls to the canyon below. Assume that the only acceleration is due to gravity: 9.8 m/sec2 downward.
(a)Write down equations for the position and velocity of the poor coyote.
(b)How much time passes before he hits the ground?
(c)What is his velocity after 4 seconds?
here ,
the height of building , h0 = 300 m
a)
the equation of position ,
from second equation of motion ,
h - h0 = 0 + 0.5 * g * t^2
(h + 300) = 0.5 * 9.8 * t^2
h = 4.9 * t^2 - 300 .....(1)
using first equation of motion
the equation of velocity
v = 0 - g * t
v = - g * t ....(2)
b)
when it hits the ground , h = 0
using (1)
0 = 4.9 * t^2 - 300
t = 7.8 s
c)
at t1 = 4 s
the velocity , v = - g * 4 = - 39.2 m/s
the velocity is 39.2 m/s downward
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