For water, Kf = 1.86 °C∙kg/mole, Kb = 0.52 °C∙kg/mole and density = 1.00 g/mL. Calculate the boiling and freezing points of the following aqueous solutions: a) 18.4 g of glucose (C6H12O6) in 95.5 g of water. b) 15.0 g of magnesium fluoride in 75.0 mL water.
For water, Kf = 1.86 °C∙kg/mole, Kb = 0.52 °C∙kg/mole and density = 1.00 g/mL. Calculate...
Molal Boiling-Point-Elevation and Freezing-Point-Depression Solvent Normal Boiling Point (∘C) Kb (∘C/m) Normal Freezing Point (∘C) Kf (∘C/m) Water, H2O 100.0 0.51 0.0 1.86 Benzene, C6H6 80.1 2.53 5.5 5.12 Ethanol, C2H5OH 78.4 1.22 -114.6 1.99 Carbon tetrachloride, CCl4 76.8 5.02 -22.3 29.8 Chloroform, CHCl3 61.2 3.63 -63.5 4.68 Part E freezing point of 2.02 g KBr and 4.84 g glucose (C6H12O6) in 187 g of water Part F boiling point of 2.02 g KBr and 4.84 g glucose (C6H12O6) in...
A solution of water (Kf=1.86 ∘C/m) and glucose freezes at − 2.35 ∘C. What is the molal concentration of glucose in this solution? Assume that the freezing point of pure water is 0.00 ∘C. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) m m m = nothing nothing Submit Boiling points and molality Similar to the freezing-point depression, the boiling-point elevation ΔTb of a solution is quantitatively related to the molality m and...
- Boiling point and Freezing point Elevation Calculate the boiling point and freezing points of water solutions that are 1.50 Min the KCl, a strong electrolyte. (the kb for water is 0.52", kf = 1.86)
Questions number 5 5. An aqueous solution of glucose (C6H1206) freezes at -5.25°C (Kf for water = 1.86 °C/n, Kb for water = 0.512 °C/n, freezing point of water = 0.00°C; boiling point of water = 100.0°C) a) Calculate the molality of the solution (S-points) Showu wrand worke b) Calculate the boiling point of the solution. (5 points) Show all set up and work !
a) If 1.95 mol of calcium chloride is added to 2.30 kg of water then what is the freezing point lowering and the freezing point of the solution (Kf = 1.86 ºC/m)? b) If 0.500 mol of NaCl is added to 500 mL of water then what is the boiling point elevation and the boiling point of the solution (Kb = 0.52 ºC/m)?
What is the freezing point in ∘C of each of the solutions below? For water, Kf = 1.86(∘C ⋅ kg)/mol. A solution of 15.0 g of LiCl in 168.0 g of water at 45.0 ∘C, assuming complete dissociation.
An aqueous sucrose solution freezes at -0.210 degree C. Calculate the normal boiling point and the molality of an aqueous glucose solution having the same vapor pressure. Assume ideal solution behavior and kf and kb for water are 1.86 and 0.52 K-kg/mol, respectively.
Some ethylene glycol (OHCH2CH2OH) was added to your car's cooling system along with 5.0 kg of water.a. if the freezing point of the solution is -15.0 degrees celcius, what mass in grams of glycol must have been added? Kf(H2O)=1.86 degrees celcius kg mol^-1.b. What is the boiling point of the coolant mixture? Kb(H20) = 0.52 degrees celcius kg mol^-1.
Show Intro/Instructi ater has a Kf of-1.86 °C/m. Calculate the new freezing point of an aqueous solution made by mixing 31.92 g water and 1.34 g MgCl2. Preview | Points possible: 1 Unlimited attempts. Submit
A glucose solution contains 51.8 g of glucose (C6H12O6) in 415 g of water. Calculate the freezing point of the solution. (Assume a density of 1.00 g/mL for water.)