Question

C++ Programming: Customer file

Can same one help me out with a example finsih and working programm ?

Program a simple customer file. Each customer should be defined as a class customer can be modelled with the following attributes: Last name, first name, unique Customer number, postcode, place of residence. Implement the following menu for this:
(e) Enter a new customer from Keypad
(l) Deleting a customer
(a) Output of all customers
(x) Exit
Comments:
- At point (e) the unique customer number should be assigned automatically.
- At point (l) a number x is read in first. Customer no. x is then deleted. Make sure that only customers that exist are deleted (checking the valid range). There are many different Possible solutions. It is therefore essential that you leave a short comment, that describes how your solution works.

Answer 1

Please let me know if u need more info:-

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#include <iostream>

#include <list>

#include <iterator>

#include <string>

using namespace std;

class Customer {

public :

string firstName;

string lastName;

int custNumber;

int postcode;

string city;

bool operator == (const Customer& c) const { return custNumber == c.custNumber; }

bool operator != (const Customer& c) const { return !operator==(c); }

};

void printMenu(){

cout<<"(e) Enter a new customer from Keypad"<<endl;

cout<<"(l) Deleting a customer"<<endl;

cout<<"(a) Output of all customers"<<endl;

cout<<"(x) Exit"<<endl;

cout<<"Your choice: ";

}

int main() {

list <Customer> customers;

while(1){

char choice;

printMenu();

cin>>choice;

if(choice == 'e' || choice == 'E'){

Customer customer;

customer.custNumber = customers.size() + 1;

cout<<"Enter first name: ";

cin>>customer.firstName;

cout<<"Enter last name: ";

cin>>customer.lastName;

cout<<"Enter post code: ";

cin>>customer.postcode;

cout<<"Enter place of residence: ";

cin>>customer.city;

customers.push_back(customer);

}else if(choice == 'l' || choice == 'L'){

int custNum = 0;

cout<<"Enter customer number: ";

cin>>custNum;

list <Customer> :: iterator it = customers.begin();

while (it != customers.end()) {

if(it->custNumber == custNum){

it = customers.erase(it);

} else{

it++;

}

}

}else if(choice == 'a' || choice == 'A'){

list <Customer> :: iterator it;

for(it = customers.begin(); it != customers.end(); ++it) {

cout<<"Customer Number: " << it->custNumber <<endl;

cout<<"Customer First Name: " << it->firstName <<endl;

cout<<"Customer Last Name: " << it->lastName <<endl;

cout<<"Customer post code: " << it->postcode <<endl;

cout<<"Customer place of residence.: " << it->city <<endl;

cout<<"============================================= " << endl;

}

}

else if(choice == 'x' || choice == 'X'){

break;

}else{

cout<<"Enter Proper choice"<<endl;

}

}

}

=======================

OUTPUT:-

==============

(e) Enter a new customer from Keypad
(l) Deleting a customer
(a) Output of all customers
(x) Exit
Your choice: e
Enter first name: s
Enter last name: d
Enter post code: 2
Enter place of residence: e
(e) Enter a new customer from Keypad
(l) Deleting a customer
(a) Output of all customers
(x) Exit
Your choice: a
Customer Number: 1
Customer First Name: s
Customer Last Name: d
Customer post code: 2
Customer place of residence.: e
=============================================
(e) Enter a new customer from Keypad
(l) Deleting a customer
(a) Output of all customers
(x) Exit
Your choice: l
Enter customer number: 1
(e) Enter a new customer from Keypad
(l) Deleting a customer
(a) Output of all customers
(x) Exit
Your choice: a
(e) Enter a new customer from Keypad
(l) Deleting a customer
(a) Output of all customers
(x) Exit
Your choice: x

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Thanks