Given 1.0 mL of methyl benzoate, 3.0 mL conc. H2SO4, 1.0 mL of concentrated nitric acid...
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Given 1.0 mL of methyl benzoate, 3.0 mL conc. H2SO4, 1.0 mL of
concentrated nitric acid...
Consider the nitration of methyl benzoate by concentrated nitric and sulfuric acids via an electrophilic aromatic...
Consider the nitration of
methyl benzoate by concentrated nitric and sulfuric acids via an
electrophilic aromatic substitution to form methyl m-nitrobenzoate.
Calculate the molar masses of the reactants and product.
Consider the nitration of methyl benzoate by concentrated nitric and sulfuric acids via an electrophilic aromatic substitution to form methyl m-nitrobenzoate Calculate the molar masses of the reactants and product. O. conc. HNO3, conc. H2SO4 TE: hydrogens have been omitted for clarity. O2 Report molar masses to 1 decimal place....
What would be the theoretical yield of reacting methyl benzoate (C₆H₅CO₂CH3) with nitric acid (HNO3) and...
What would be the theoretical yield of reacting methyl benzoate (C₆H₅CO₂CH3) with nitric acid (HNO3) and sulfuric acid (H2SO4), producing methyl m-nitrobenzoate (C6H4CO2CH3NO2)? 6 g methyl benzoate 4 mL nitric acid 4 mL sulfuric acid crude methyl m-nitrobenzoate recovered: 7.260 g pure methyl m-nitrobenzoate recovered: 6.227 g
-NITRATION OF Methyl benzoate -addditional information. .( 3.9 g of the product methyl 3-nitrobenzoate for the...
-NITRATION OF Methyl benzoate
-addditional information. .( 3.9 g of the product methyl
3-nitrobenzoate for the percentage yield
Materials used: Amount Compound used/ Molecular weight Density (g/mL) Moles produced 3.05g used 136.15 g/mol N/A 0.0224 mol Methyl Benzoate HO-S-OH 6mL used 98.079 g/mol 1.83 g/cm3 0.112 Sulfuric Acid 2mL used 63.01 g/mol 1.51 g/cm3 0.047g o-N-OH Nitric Acid 3.034g of pure product 181.15 g/mol produced N/A 0.0167 mol NO2 Methyl-m- nitrobenzoate Calculating limiting reagent and theoretical yield: 0.0224 mol methylbenzoate...
Calculate the theoretical yield I got 0.0103 mols of methyl benzoate and 0.0224 mols of nitric...
Calculate the theoretical yield
I got 0.0103 mols of methyl benzoate and 0.0224 mols of nitric
acid. Methyl benzoate is the limiting reactant
4. Calculate the theoretical yield (in grams) of the methyl nitrobenzoate isomer formed in the reaction from the amounts used in the procedure. Be sure and use the limiting reagent for your caleulations. Show your work and use correct number of significant figures in your answer. 5. Yield of product:
Nitration of Methyl Benzoate to synthesize Methyl m-nitrobenzoate Find theoretical yield and percent yield. Show all...
Nitration of Methyl Benzoate to synthesize Methyl m-nitrobenzoate Find theoretical yield and percent yield. Show all steps. Results: .040 g of methyl m-nitrobenzoate crystals produced 1. Add .30 g of Methyl Benzoate to .6 ml of Sulfuric Acid in a reaction tube 2. Dropwise add a mixture of .2 ml of sulfuric acid and .2ml of nitric acid 3. After 15 min, pour onto 2.5 g of ice in a small beaker 4. Use suction filtration to dry crystals. Wash...
What would be the product(s) of this reaction if toluene replaced methyl benzoate? If only concentrated...
What would be the product(s) of this reaction if toluene replaced methyl benzoate? If only concentrated nitric acid were used in this reaction, will that increase the % yield of the reaction? And why? What is the function of concentrated sulfuric acid? Please use a reaction equation to show your answer. These are questions from my organic chemistry lab regarding the nitration of methyl benzoate to form m-nitrobenzoate through electrophilic aromatic substitution rxn.
Solution 1 (starting material): 4.0 mL of concentrated sulfuric acid is added to a flask, 2.0...
Solution 1 (starting material): 4.0 mL of concentrated sulfuric acid is added to a flask, 2.0 mL of methyl benzoate is then added to the sulfuric acid solution Solution 2 (electrophile, nitronium ion): 2.0 mL of concentrated nitric acid is added to a test tube, followed by 2.0 mL of concentrated sulfuric acid. Add solution 2 to solution 1. Calculate the theoretical yield. concebtration was not given
Methyl benzoate, which has a molar mass of 136.15 g/mol, can be nitrated to methyl nitrobenzoate,...
Methyl benzoate, which has a molar mass of 136.15 g/mol, can be nitrated to methyl nitrobenzoate, which has a molar mass of 181.13 g/mol, by the addition of nitric acid. What is the theoretical yield (in g) of the mononitrated product, methyl nitrobenzoate, from 0.560 g of methyl benzoate?
Methyl benzoate, which has a molar mass of 136.15 g/mol, can be nitrated to methyl nitrobenzoate,...
Methyl benzoate, which has a molar mass of 136.15 g/mol, can be nitrated to methyl nitrobenzoate, which has a molar mass of 181.13 g/mol, by the addition of nitric acid. What is the theoretical yield (in g) of the mononitrated product, methyl nitrobenzoate, from 0.556 g of methyl benzoate? Answer:
Nitration of Methyl Benzoate Calculations - please fill out every box and expected and percent yield....
Nitration of Methyl Benzoate Calculations - please fill out
every box and expected and percent yield.
- eqt: methyl benzoate + HNO3
----->(H2SO4 above arrow)
Methyl-m-nitrobenzoate + H2O
- end product= 2.105 g
-2ml of nitric acid and 2ml of sulfuric acid were used
Calculation of Theoretical Yield Balanced Equation: RAH OH M.W.*: 18.00 g/mol 136.15 g mos 63.0lgimo 4.026g 31.505g 181.15 Horg grams*: moles*: * Include these values for all compounds, underneath that compound, in the balanced equation. Limiting...
Consider the nitration of
methyl benzoate by concentrated nitric and sulfuric acids via an
electrophilic aromatic substitution to form methyl m-nitrobenzoate.
Calculate the molar masses of the reactants and product.
Consider the nitration of methyl benzoate by concentrated nitric and sulfuric acids via an electrophilic aromatic substitution to form methyl m-nitrobenzoate Calculate the molar masses of the reactants and product. O. conc. HNO3, conc. H2SO4 TE: hydrogens have been omitted for clarity. O2 Report molar masses to 1 decimal place....
-NITRATION OF Methyl benzoate
-addditional information. .( 3.9 g of the product methyl
3-nitrobenzoate for the percentage yield
Materials used: Amount Compound used/ Molecular weight Density (g/mL) Moles produced 3.05g used 136.15 g/mol N/A 0.0224 mol Methyl Benzoate HO-S-OH 6mL used 98.079 g/mol 1.83 g/cm3 0.112 Sulfuric Acid 2mL used 63.01 g/mol 1.51 g/cm3 0.047g o-N-OH Nitric Acid 3.034g of pure product 181.15 g/mol produced N/A 0.0167 mol NO2 Methyl-m- nitrobenzoate Calculating limiting reagent and theoretical yield: 0.0224 mol methylbenzoate...
Calculate the theoretical yield
I got 0.0103 mols of methyl benzoate and 0.0224 mols of nitric
acid. Methyl benzoate is the limiting reactant
4. Calculate the theoretical yield (in grams) of the methyl nitrobenzoate isomer formed in the reaction from the amounts used in the procedure. Be sure and use the limiting reagent for your caleulations. Show your work and use correct number of significant figures in your answer. 5. Yield of product:
Methyl benzoate, which has a molar mass of 136.15 g/mol, can be nitrated to methyl nitrobenzoate, which has a molar mass of 181.13 g/mol, by the addition of nitric acid. What is the theoretical yield (in g) of the mononitrated product, methyl nitrobenzoate, from 0.556 g of methyl benzoate? Answer:
Nitration of Methyl Benzoate Calculations - please fill out
every box and expected and percent yield.
- eqt: methyl benzoate + HNO3
----->(H2SO4 above arrow)
Methyl-m-nitrobenzoate + H2O
- end product= 2.105 g
-2ml of nitric acid and 2ml of sulfuric acid were used
Calculation of Theoretical Yield Balanced Equation: RAH OH M.W.*: 18.00 g/mol 136.15 g mos 63.0lgimo 4.026g 31.505g 181.15 Horg grams*: moles*: * Include these values for all compounds, underneath that compound, in the balanced equation. Limiting...
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