What would be the theoretical yield of reacting methyl benzoate (C₆H₅CO₂CH3) with nitric acid (HNO3) and...
What would be the theoretical yield of reacting methyl benzoate (C₆H₅CO₂CH3) with nitric acid (HNO3) and sulfuric acid (H2SO4), producing methyl m-nitrobenzoate (C6H4CO2CH3NO2)?
6 g methyl benzoate
4 mL nitric acid
4 mL sulfuric acid
crude methyl m-nitrobenzoate recovered: 7.260 g
pure methyl m-nitrobenzoate recovered: 6.227 g
Homework Answers
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What would be the theoretical yield of reacting methyl benzoate
(C₆H₅CO₂CH3) with nitric acid (HNO3) and...
Nitration of Methyl Benzoate to synthesize Methyl m-nitrobenzoate Find theoretical yield and percent yield. Show all...
Nitration of Methyl Benzoate to synthesize Methyl m-nitrobenzoate Find theoretical yield and percent yield. Show all steps. Results: .040 g of methyl m-nitrobenzoate crystals produced 1. Add .30 g of Methyl Benzoate to .6 ml of Sulfuric Acid in a reaction tube 2. Dropwise add a mixture of .2 ml of sulfuric acid and .2ml of nitric acid 3. After 15 min, pour onto 2.5 g of ice in a small beaker 4. Use suction filtration to dry crystals. Wash...
Nitration of Methyl Benzoate Calculations - please fill out every box and expected and percent yield....
Nitration of Methyl Benzoate Calculations - please fill out
every box and expected and percent yield.
- eqt: methyl benzoate + HNO3
----->(H2SO4 above arrow)
Methyl-m-nitrobenzoate + H2O
- end product= 2.105 g
-2ml of nitric acid and 2ml of sulfuric acid were used
Calculation of Theoretical Yield Balanced Equation: RAH OH M.W.*: 18.00 g/mol 136.15 g mos 63.0lgimo 4.026g 31.505g 181.15 Horg grams*: moles*: * Include these values for all compounds, underneath that compound, in the balanced equation. Limiting...
-NITRATION OF Methyl benzoate -addditional information. .( 3.9 g of the product methyl 3-nitrobenzoate for the...
-NITRATION OF Methyl benzoate
-addditional information. .( 3.9 g of the product methyl
3-nitrobenzoate for the percentage yield
Materials used: Amount Compound used/ Molecular weight Density (g/mL) Moles produced 3.05g used 136.15 g/mol N/A 0.0224 mol Methyl Benzoate HO-S-OH 6mL used 98.079 g/mol 1.83 g/cm3 0.112 Sulfuric Acid 2mL used 63.01 g/mol 1.51 g/cm3 0.047g o-N-OH Nitric Acid 3.034g of pure product 181.15 g/mol produced N/A 0.0167 mol NO2 Methyl-m- nitrobenzoate Calculating limiting reagent and theoretical yield: 0.0224 mol methylbenzoate...
Consider the nitration of methyl benzoate by concentrated nitric and sulfuric acids via an electrophilic aromatic...
Consider the nitration of
methyl benzoate by concentrated nitric and sulfuric acids via an
electrophilic aromatic substitution to form methyl m-nitrobenzoate.
Calculate the molar masses of the reactants and product.
Consider the nitration of methyl benzoate by concentrated nitric and sulfuric acids via an electrophilic aromatic substitution to form methyl m-nitrobenzoate Calculate the molar masses of the reactants and product. O. conc. HNO3, conc. H2SO4 TE: hydrogens have been omitted for clarity. O2 Report molar masses to 1 decimal place....
Calculate the theoretical yield I got 0.0103 mols of methyl benzoate and 0.0224 mols of nitric...
Calculate the theoretical yield
I got 0.0103 mols of methyl benzoate and 0.0224 mols of nitric
acid. Methyl benzoate is the limiting reactant
4. Calculate the theoretical yield (in grams) of the methyl nitrobenzoate isomer formed in the reaction from the amounts used in the procedure. Be sure and use the limiting reagent for your caleulations. Show your work and use correct number of significant figures in your answer. 5. Yield of product:
Calculate the theoretical yield and percent yield for experiments 7, 8, and 9. For experiment 9,...
Calculate the theoretical yield and percent yield for
experiments 7, 8, and 9. For experiment 9, determine the
theoretical yield based on starting with 0.50g of 3-nitrobenzoic
acid. Show work
Acid I (experiment 7): Weight of methyl 3-nitrobenzoate = 1.9
g
Acid II (experiment 8): Weight of 3-nitrobenzoic acid = 1.75
g
Acid III (experiment 9): Weight of 3-nitrobenzamide = 0.30 g
Experiment 7:
-2.5 mL concentrated H2SO4
-1.75 mL concentrated HNO3 (16M)
-2.1 mL concentrated Methyl Benzoate
Experiment 8:...
Calculating Theoretical Yield While making methyl 3-Nitrobenzoate during orgo lab we were asked to calculate theoretical...
Calculating Theoretical Yield While making methyl 3-Nitrobenzoate during orgo lab we were asked to calculate theoretical yield and I not sure how to start correctly. We used 7.5ml of 18M H2SO4, and also 2.5 18M H2SO4 & 2.5mL of 16M HNO3. Then we added 2.1ml of methyl benzoate (d=1.09 g/ml) to the 7.5ml of H2SO4. Once that was all mixed, the H2SO4 & HNO3 was added to the H2SO4- menthyl benzoate mixture. Then we filtered it using suction filtration. (adding...
What would be the product(s) of this reaction if toluene replaced methyl benzoate? If only concentrated...
What would be the product(s) of this reaction if toluene replaced methyl benzoate? If only concentrated nitric acid were used in this reaction, will that increase the % yield of the reaction? And why? What is the function of concentrated sulfuric acid? Please use a reaction equation to show your answer. These are questions from my organic chemistry lab regarding the nitration of methyl benzoate to form m-nitrobenzoate through electrophilic aromatic substitution rxn.
PROCEDURE CAUTION!!! Nitric acid and sulfuric acid are strong and corrosive acids. For that reason, avoid...
PROCEDURE CAUTION!!! Nitric acid and sulfuric acid are strong and corrosive acids. For that reason, avoid inhaling its vapors or causing any contact with the skin or clothing. Wear your protective glasses at all times. Use the extractors to work with these acids. A. Nitration of methyl benzoate 1. Preparation of the reactants. In the extractor you will find a burette with concentrated sulfuric acid, a second burette with concentrated nitric acid, clearly identified. Familiarize yourself with the scales of...
QUESTIONS 1. Why does methyl benzoate dissolve in concentrated sulfuric acid? 2. What is the EQUATION...
QUESTIONS 1. Why does methyl benzoate dissolve in concentrated sulfuric acid? 2. What is the EQUATION for the reaction between concentrated nitric and sulfuric acids? 3. What is the DOT STRUCTURE for NO,"? 4. What is the MECHANISM for the formation of m-nitromethylbenzoate? 5. WHY does reaction occur at the META position only? 6. What is the PURITY of the m-nitromethylbenzoate recovered based on its melting range?
Nitration of Methyl Benzoate Calculations - please fill out
every box and expected and percent yield.
- eqt: methyl benzoate + HNO3
----->(H2SO4 above arrow)
Methyl-m-nitrobenzoate + H2O
- end product= 2.105 g
-2ml of nitric acid and 2ml of sulfuric acid were used
Calculation of Theoretical Yield Balanced Equation: RAH OH M.W.*: 18.00 g/mol 136.15 g mos 63.0lgimo 4.026g 31.505g 181.15 Horg grams*: moles*: * Include these values for all compounds, underneath that compound, in the balanced equation. Limiting...
-NITRATION OF Methyl benzoate
-addditional information. .( 3.9 g of the product methyl
3-nitrobenzoate for the percentage yield
Materials used: Amount Compound used/ Molecular weight Density (g/mL) Moles produced 3.05g used 136.15 g/mol N/A 0.0224 mol Methyl Benzoate HO-S-OH 6mL used 98.079 g/mol 1.83 g/cm3 0.112 Sulfuric Acid 2mL used 63.01 g/mol 1.51 g/cm3 0.047g o-N-OH Nitric Acid 3.034g of pure product 181.15 g/mol produced N/A 0.0167 mol NO2 Methyl-m- nitrobenzoate Calculating limiting reagent and theoretical yield: 0.0224 mol methylbenzoate...
Consider the nitration of
methyl benzoate by concentrated nitric and sulfuric acids via an
electrophilic aromatic substitution to form methyl m-nitrobenzoate.
Calculate the molar masses of the reactants and product.
Consider the nitration of methyl benzoate by concentrated nitric and sulfuric acids via an electrophilic aromatic substitution to form methyl m-nitrobenzoate Calculate the molar masses of the reactants and product. O. conc. HNO3, conc. H2SO4 TE: hydrogens have been omitted for clarity. O2 Report molar masses to 1 decimal place....
Calculate the theoretical yield
I got 0.0103 mols of methyl benzoate and 0.0224 mols of nitric
acid. Methyl benzoate is the limiting reactant
4. Calculate the theoretical yield (in grams) of the methyl nitrobenzoate isomer formed in the reaction from the amounts used in the procedure. Be sure and use the limiting reagent for your caleulations. Show your work and use correct number of significant figures in your answer. 5. Yield of product:
Calculate the theoretical yield and percent yield for
experiments 7, 8, and 9. For experiment 9, determine the
theoretical yield based on starting with 0.50g of 3-nitrobenzoic
acid. Show work
Acid I (experiment 7): Weight of methyl 3-nitrobenzoate = 1.9
g
Acid II (experiment 8): Weight of 3-nitrobenzoic acid = 1.75
g
Acid III (experiment 9): Weight of 3-nitrobenzamide = 0.30 g
Experiment 7:
-2.5 mL concentrated H2SO4
-1.75 mL concentrated HNO3 (16M)
-2.1 mL concentrated Methyl Benzoate
Experiment 8:...
PROCEDURE CAUTION!!! Nitric acid and sulfuric acid are strong and corrosive acids. For that reason, avoid inhaling its vapors or causing any contact with the skin or clothing. Wear your protective glasses at all times. Use the extractors to work with these acids. A. Nitration of methyl benzoate 1. Preparation of the reactants. In the extractor you will find a burette with concentrated sulfuric acid, a second burette with concentrated nitric acid, clearly identified. Familiarize yourself with the scales of...
QUESTIONS 1. Why does methyl benzoate dissolve in concentrated sulfuric acid? 2. What is the EQUATION for the reaction between concentrated nitric and sulfuric acids? 3. What is the DOT STRUCTURE for NO,"? 4. What is the MECHANISM for the formation of m-nitromethylbenzoate? 5. WHY does reaction occur at the META position only? 6. What is the PURITY of the m-nitromethylbenzoate recovered based on its melting range?
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