For the hydrogen atom from the previous problem, calculate the ratio (F_e/F_g) of the electric force...
For the hydrogen atom from the previous problem, calculate the ratio (F_e/F_g) of the electric force to the gravitational force (m_e = 9.11x10^-31 kg, m_p = 1.67x10^-27 kg). This ratio will show by how much greater the electric force is than the gravitational force (ie, a ratio = 1 would imply the forces are of equal strength).
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For the hydrogen atom from the previous problem, calculate the
ratio (F_e/F_g) of the electric force...
Example 15.1 The Forces in a Hydrogen Atom Goal Contrast the magnitudes of an electric force...
Example 15.1 The Forces in a Hydrogen Atom Goal Contrast the magnitudes of an electric force and a gravitational force. Problem The electron and proton of a hydrogen atom are separated (on the average) by a distance of about 5.30 x 1011 m. Find the magnitudes of the electric force and the gravitational force that each particle exerts on the other, and the ratio of the electric force, Fe, to the gravitational force, Fo Strategy Solving this problem is just...
In the Bohr model of the Hydrogen atom, a single electron orbits around a single proton...
In the Bohr model of the Hydrogen atom, a single electron orbits around a single proton (which constitutes the nucleus). The mass of the electron (9.11x10-31 kg) is much less than the proton (1.67x10-27 kg), so the proton remains stationary while the electron moves around it. If the electron is 6.6x10-11 m away from the proton, calculate the magnitude of the electric force (in N) exerted by the proton on the electron. b) [Continued ...] In the Bohr model, an...
Consider a simplified model of a triply ionized beryllium-9 atom (Be^1+): four protons plus five neutrons...
Consider a simplified model of a triply ionized beryllium-9 atom (Be^1+): four protons plus five neutrons in the atom's nucleus, "orbited" by just one electron at a constant distance of 4.50 times 10^-12 m. You can solve (a) & (b) in either order. Label your work clearly: a. What is the strength (magnitude) of the attractive electric force between the nucleus and the electron? Show your work. b. What is the magnitude of the electric field at the electron's location?...
It is known that the electric force of repulsion between two electrons is much stronger than...
It is known that the electric force of repulsion between two electrons is much stronger than the gravitational attraction. For two electrons at a distance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction at a disance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction Use the following data: k-8.99x 109 Nm2/C2, e-1.60x10-19 C, G-6.67x10-11 Nm2/kg2, me 9.11x10-31 kg.
It is known that the electric force of repulsion between two electrons is much stronger than...
It is known that the electric force of repulsion between two electrons is much stronger than the gravitational attraction. For two electrons at a distance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction. Use the following data: k = 8.99 Times 10^9 Nm^2/C^2, e = 1.60 Times 10^-19 C, G = 6.67 Times 10^-11 Nm^2/kg^2, m_e = 9.11 Times 10^-31 kg. Tries 0/20
I need help with these questions. 1. Calculate the force of graviational attraction between an SUV,...
I need help with these questions. 1. Calculate the force of graviational attraction between an SUV, mass-2000kg, and the Earth. 2. Calculate the gravitational field strength on the surface of Ganymede. How does this compare to the Earth? Our Moon? 3. Calculate the force of gravitational attraction between two carbon 16 atoms when theya re 1x10^-13 m apart. The mass of a proton or a neutron is 1.67x10^-27 kg, and the mass of an electron is 9.11x10^-31 4. Mary weighs...
A hydrogen atom is at the earth’s surface. The electron and proton in the atom are...
A hydrogen atom is at the earth’s surface. The electron and
proton in the atom are separated by a distance of 5.29×10?11m. What
is the ratio of the magnitude of the electric force exerted by the
proton on the electron to the weight of the electron?
r-529 x1σ11 m Mp= 1.67×10 -27 kg /n-911 × 10-31 kg
The electric force is much stronger than the gravitational force so we can often neglect gravity...
The electric force is much stronger than the gravitational force
so we can often neglect gravity in electricity and magnetism. How
far does the electron of a hydrogen atom have to be removed from
the nucleus (contains only one proton) for the force of attraction
equal the weight of the electron at the surface of the Earth (g=9.8
m/s2)? Is that large compared to the size of an atom?
2. The electric force is much stronger than the gravitational force...
2. Consider a simplified model of a triply ionized beryllium-9 atom (Be): four protons plus five...
2. Consider a simplified model of a triply ionized beryllium-9 atom (Be): four protons plus five neutrons in the atom's nucleus, "orbited" by just one electron at a constant distance of 5.75 × 10-12 m. (Note: This is not the actual distance, but it is the correct order-of-magnitude.) 6 pts.) You can solve (a) & (b) in either order. Label your work clearly: a. What is the strength (magnitude) of the attractive electric force between the nucleus and the electron?...
Sorry this problem has so many parts--thank you in advance for your effort. Which Force Is...
Sorry this problem has so many
parts--thank you in advance for your effort.
Which Force Is Stronger-Electrical or Gravitational? Let's peek into the hydrogen atom and compare the gravitational force on the electron due to interaction of its mass with that of the proton to the electrical force between the two particles as a result of their charges. In order to do the calcula- tion, you'll need to use some well-known values: Electron: me-9.1 × 10-31 Kg qe =-1.6 ×...
Example 15.1 The Forces in a Hydrogen Atom Goal Contrast the magnitudes of an electric force and a gravitational force. Problem The electron and proton of a hydrogen atom are separated (on the average) by a distance of about 5.30 x 1011 m. Find the magnitudes of the electric force and the gravitational force that each particle exerts on the other, and the ratio of the electric force, Fe, to the gravitational force, Fo Strategy Solving this problem is just...
Consider a simplified model of a triply ionized beryllium-9 atom (Be^1+): four protons plus five neutrons in the atom's nucleus, "orbited" by just one electron at a constant distance of 4.50 times 10^-12 m. You can solve (a) & (b) in either order. Label your work clearly: a. What is the strength (magnitude) of the attractive electric force between the nucleus and the electron? Show your work. b. What is the magnitude of the electric field at the electron's location?...
It is known that the electric force of repulsion between two electrons is much stronger than the gravitational attraction. For two electrons at a distance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction at a disance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction Use the following data: k-8.99x 109 Nm2/C2, e-1.60x10-19 C, G-6.67x10-11 Nm2/kg2, me 9.11x10-31 kg.
It is known that the electric force of repulsion between two electrons is much stronger than the gravitational attraction. For two electrons at a distance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction. Use the following data: k = 8.99 Times 10^9 Nm^2/C^2, e = 1.60 Times 10^-19 C, G = 6.67 Times 10^-11 Nm^2/kg^2, m_e = 9.11 Times 10^-31 kg. Tries 0/20
A hydrogen atom is at the earth’s surface. The electron and
proton in the atom are separated by a distance of 5.29×10?11m. What
is the ratio of the magnitude of the electric force exerted by the
proton on the electron to the weight of the electron?
r-529 x1σ11 m Mp= 1.67×10 -27 kg /n-911 × 10-31 kg
The electric force is much stronger than the gravitational force
so we can often neglect gravity in electricity and magnetism. How
far does the electron of a hydrogen atom have to be removed from
the nucleus (contains only one proton) for the force of attraction
equal the weight of the electron at the surface of the Earth (g=9.8
m/s2)? Is that large compared to the size of an atom?
2. The electric force is much stronger than the gravitational force...
2. Consider a simplified model of a triply ionized beryllium-9 atom (Be): four protons plus five neutrons in the atom's nucleus, "orbited" by just one electron at a constant distance of 5.75 × 10-12 m. (Note: This is not the actual distance, but it is the correct order-of-magnitude.) 6 pts.) You can solve (a) & (b) in either order. Label your work clearly: a. What is the strength (magnitude) of the attractive electric force between the nucleus and the electron?...
Sorry this problem has so many
parts--thank you in advance for your effort.
Which Force Is Stronger-Electrical or Gravitational? Let's peek into the hydrogen atom and compare the gravitational force on the electron due to interaction of its mass with that of the proton to the electrical force between the two particles as a result of their charges. In order to do the calcula- tion, you'll need to use some well-known values: Electron: me-9.1 × 10-31 Kg qe =-1.6 ×...
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