A. How many millimoles of magnesium chloride are there in 4 liters of 0.2 M MgCl2
a. How many nanomoles are in 2.3 x 10-1 μmoles?
A)
4 liters of 0.2 M MgCl2 = volume of solution in L * molarity = 4.0 L * 0.2 mole / L = 0.8 mole.
we know,
1 mole = 1000 mmole.
thus
0.8 mole = 0.8 * 1000 = 800 mmole (answer)
a)
we know,
1 μmole = 1000 nanomoles
thus
2.3 x 10-1 μmoles = 2.3 x 10-1 * 1000 = 230 nanomoles (answer)
A. How many millimoles of magnesium chloride are there in 4 liters of 0.2 M MgCl2...
How many grams of magnesium chloride (MgCl2) must be added to 23.0 g of water to prepare a 6.92% (m/m) solution of magnesium chloride?
7 g of magnesium chloride (MgCl2) is dissolved in 2.40 L of water. 11g/mole) (15 pts) a. What is the molarity of solution? b. How many moles of MgCl2 are contained in 1.76L of solver C. How many liters of solvent would contain 0.0150 moles of 45.7 g of magnesium chloride (MgCl) is dissolved in 2.40 L of water. (Molar mass of 95.11g/mole) (15 pts) a. What is the molarity of solution? b. How many moles of MgCl2 are contained...
How many formula units make up 18.4 g of magnesium chloride (MgCl2)?
How many formula units make up 36.2 g of magnesium chloride (MgCl2)
How many formula units make up 12.8 g of magnesium chloride (MgCl2)? Express the number of formula units numerically.
A tablet contains 238 mg of magnesium chloride (MgCl2 MW = 95.2 g/mol). How many milliequivalents of magnesium ions does the tablet contain? Assume complete disassociation. (Round your answer to the nearest whole number of milliequivalents. How is this worked out? The answer is 5
1.) How many millimoles of 10mg/L of potassium chloride if MW is 74.5? 2.) How many millimoles of 10mg/L of monobasic sodium phosphate NaHPO4 (MW is 138)?
Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s) A mixture of 41.0 g of magnesium ( mm= 24.31 g/mol) and 171 g of iron(III) chloride ( mm= 162.2 g/mol) is allowed to react. MMof MgCl2=105.216 g/mol. 1. What is the limiting reactant? 2. how many grams of excess reactants will remain? 3. How many grams of MgCl2 will be formed? 4. If 142...
Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s) A mixture of 41.0 g of magnesium ( mm= 24.31 g/mol) and 175 g of iron(III) chloride ( mm= 162.2 g/mol) is allowed to react. MMof MgCl2=105.216 g/mol. 1. What is the limiting reactant? 2. how many grams of excess reactants will remain? 3. How many grams of MgCl2 will be formed? 4. If 142...
18) How many milliequivalents, meq, of magnesium ion (ie, "moles of charge carried by magnesium ion" slide CH6#59) are present in a solution that contains 0.030 moles of magnesium chloride? 19) How many milliequivalents, meq, of sodium ion (ie, "moles of charge carried by sodium ion": slide CH6859) are present in a 1.0 L of 0.154 M sodium chloride solution? 20) A 5%(m/v) dextrose IV fluid (D,W) is supplemented with 20 mEq of K* per liter of a solution. If...