Question

In C++ Prompts the user to enter 5 numbers. Once the user has entered the 5 numbers, the program should calculate and display the average of the 5 numbers.and no for(;;) while(1) while(true) do{//code}while(1); without cin The program prompts the user for one number at a time

Answer 1

If we are not using cin, then we have to use scanf() function to get the input from the user. In this program, we created only two variables total_sum to keep adding the number to it and number to store the new number from the user.

In the end, we divide the total_sum by 5 and store it again in the total_sum variable and print it in the console.

Please Note: (I have not used for, while, do while and also cin )

here is the C++ code

-----------------------------------------------------------------------------------------------------------------------------------------------

#include<stdio.h>

#include<iostream>

int main()
{
// it will store the total sum of the 5 numbers
double total_sum=0;
// to store the next user number
double number=0;

printf("Enter a number: ");
scanf("%lf",&number);
total_sum += number;
  
printf("Enter a number: ");
scanf("%lf",&number);
total_sum +=number;
  
printf("Enter a number: ");
scanf("%lf",&number);
total_sum+=number;
  
printf("Enter a number: ");
scanf("%lf",&number);
total_sum+=number;
  
printf("Enter a number: ");
scanf("%lf",&number);
total_sum+=number;

// compute average and print
printf("\nAverage of these numbers: %.2f",total_sum/5);

}

-----------------------------------------------------------------------------------------------------------------------------------------------

thank you !