Question

The half-life of a reaction between constant concentrations of reactants varies with temperature as follows: T...

The half-life of a reaction between constant concentrations of reactants varies with temperature as follows:

T (K)                      520     533     555     574     604     620

T1/2 (s)                  1288     813     562     477     89,0    49

Calculate the activation energy for this reaction.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Everything I have explained in a neat and clean way with proper explanation, for all that you need to see just this attachment, hope you will love the solution/explanation like this, Thank you :) and have a good day ahead !!!

Add a comment
Know the answer?
Add Answer to:
The half-life of a reaction between constant concentrations of reactants varies with temperature as follows: T...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 7. In two trials with identical starting concentrations of reactants, the rate increases by a factor...

    7. In two trials with identical starting concentrations of reactants, the rate increases by a factor of 3.27 when the temperature is increased from 400 K to 670 K. What is the activation energy for this reaction? Express your answer in kJ / mol. 8. The activation energy for a particular reaction is 4.8 kJ mol-1. The temperature in one trial reaction is 350 K. To what temperature must the reaction be heated to increase the rate constant by a...

  • The Arrhenius equation shows the relationship between the rate constant k and the temperature T in...

    The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...

  • The Arrhenius equation shows the relationship between the rate constant k and the temperature T in...

    The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...

  • For a first-order reaction, the half-life is constant. It depends only on the rate constant k...

    For a first-order reaction, the half-life is constant. It depends only on the rate constant k k and not on the reactant concentration. It is expressed as t1/2=0.693k t 1 / 2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0. A certain first-order reaction (A→products A → p r o d u c t s ) has a rate constant of 9.30×10−3...

  • The Arrhenius equation shows the relationship between the rate constant k and the temperature T in...

    The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...

  • For the following first order reaction, the half-life is 28.3 and the [A]0 = 1.36. Calculate the rate constant.

    A.For the following first order reaction, the half-life is 28.3 and the [A]0  = 1.36. Calculate the rate constant.2A -> 3BB.Consider the following reaction. aA + bB -> cCwhose first and second half-lives are 38.2 and 19.1 minutes respectively. If the rate constant is equal to 0.2148 and [A]0 = 16.41, calculate the [A] at t 5.87 minutes.C.A researcher raises the temperature from 46.4 to 66 °C and finds that the rate of the reaction doubles. What was the activation energy (in...

  • #14 Rate Constant and Temperature 1. The rate constant (k) for a reaction was measured as...

    #14 Rate Constant and Temperature 1. The rate constant (k) for a reaction was measured as a function of temperature. A plot of lnk versus 1/T (in K) is linear and has a slope of -1.01 x 104 K. Calculate the activation energy for this reaction. 2. The rate constant of a reaction at 32.0oC is 0.0550 s-1. If the frequency factor is 1.20 x 1013 s-1, what is the activation energy? 3. A reaction has a rate constant of...

  • The equilibrium constant, K, of a reaction at a particular temperature is determined by the concentrations...

    The equilibrium constant, K, of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium. For a gaseous reaction with the general form aA+bB⇌cC+dD the Kc and Kp expressions are given by Kc=[C]c[D]d[A]a[B]b Kp=(PC)c(PD)d(PA)a(PB)b The subscript c or p indicates whether K is expressed in terms of concentrations or pressures. Equilibrium-constant expressions do not include a term for any pure solids or liquids that may be involved since their composition...

  • Deriving concentrations from data The equilibrium constant, K, of a reaction at a particular temperature is...

    Deriving concentrations from data The equilibrium constant, K, of a reaction at a particular temperature is detemined by the concentrations or pressures of the reactants and products at equilibrium. In Part A, you were given the equilibrium pressures, which could be plugged directly into the formula for K. In Part B however, you will be given initial concentrations and only one equilibrium concentration. You must use this data to find all three equilibrium concentrations before you can apply the formula...

  • Reaction Rates and Temperature 31 Review Constants i Peric The rate constant of a chemical reaction...

    Reaction Rates and Temperature 31 Review Constants i Peric The rate constant of a chemical reaction increased from 0.100 - 2005 - pon raising the temperature from 250 C 350 C Learning Goal To use the Athenius equation to calculate the activation energy As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means at a higher percentage of the molecules possess the required activation energy and the reaction goes faster. This relationship is shown...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT