Question

As a part of her studies, Floretta gathered data on the length of time between dentist visits for a sample of 28 individuals. She works through the testing procedure:

• H0:μ=192; Ha:μ≠192
• α=0.05
• The test statistic is t0=x¯−μ0sn√=1.014.
• The critical values are ±t0.025=±2.052.

At the 5% significance level, does the data provide sufficient evidence to conclude that the mean length of time between dentist visits is less than 192 days?

Select the correct answer below:

We should reject the null hypothesis because t0<tα/2. So, at the 5% significance level, the data provide sufficient evidence to conclude that the average length of time between dentist visits is not equal to 192 days.

We should reject the null hypothesis because t0>−tα/2. So, at the 5% significance level, the data provide sufficient evidence to conclude that the average length of time between dentist visits is not equal to 192 days.

We should reject the null hypothesis because −tα/2<t0<tα/2. So, at the 5% significance level, the data do not provide sufficient evidence to conclude that the average length of time between dentist visits is not equal to 192 days.

We should not reject the null hypothesis because t0>−tα/2. So, at the 5% significance level, the data do not provide sufficient evidence to conclude that the average length of time between dentist visits is not equal to 192 days.

We should not reject the null hypothesis because −tα/2<t0<tα/2. So, at the 5% significance level, the data do not provide sufficient evidence to conclude that the average length of time between dentist visits is not equal to 192 days.

Answer 1

We should not reject the null hypothesis because −tα/2<t0<tα/2. So, at the 5% significance level, the data do not provide sufficient evidence to conclude that the average length of time between dentist visits is not equal to 192 days.

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