A gas mixture contains 13.2 mol of NO and 5.55 mol of Br2.
(a) Compute the mole fraction of NO in the mixture.
XNO =
(b) The mixture is then allowed to stand, and the NO starts to react with the Br2 to give NOBr: 2NO(g) + Br2(g) 2NOBr(g)
At a certain point in the reaction, 2.40 mol of NOBr is present. Determine the mole fraction of NO in the new mixture. XNO =
A gas mixture contains 13.2 mol of NO and 5.55 mol of Br2. (a) Compute the...
A student ran the following reaction in the laboratory at 295 K: 2NO(g) + Br2(g) <---> 2NOBr(g) When she introduced 0.153 moles of NO(g) and 0.123 moles of Br2(g) into a 1.00 liter container, she found the equilibrium concentration of NOBr(g) to be 0.117 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = ____ The equilibrium constant, Kc, for the following reaction is 6.50×10-3 at 298K. 2NOBr(g) <---> 2NO(g) + Br2(g) If an equilibrium mixture of...
The equilibrium constant, Kc, for the following reaction is 6.50×10-3 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 11.1 L container at 298K contains 0.376 mol of NOBr(g) and 0.396 mol of NO, the equilibrium concentration of Br2
The equilibrium constant, Kc, for the following reaction is 2.0. If the equilibrium mixture contains 1.5 M NO and 1.5 M Br2, what is the molar concentration of NOBr? 2NOBr(g)⇌2NO(g)+Br2(g) Express your answer in two significant figures
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K. In a reaction mixture at equilibrium, the partial pressure of NO is 108 torr and that of Br2 is 158 torr . What is the partial pressure of NOBr in this mixture?
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 130 torr and that of Br2 is 146 torr What is the partial pressure of NOBr in this mixture? Express your answer using three significant figures.
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 101 torr and that of Br2 is 150 torr . What is the partial pressure of NOBr in this mixture? Express your answer using three significant figures.
The equilibrium constant, Kc, for the following reaction is 2.0. If the equilibrium mixture contains 2.3 M NO and 0.80 M Br2 , what is the molar concentration of NOBr? 2NOBr(g) = 2NO(g) + Br2 (g) Express your answer to two significant figures and include the appropriate units. Å R 0 2 ? [NOBr] = Value Units Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining
Consider the following reaction: 2NO(g)+Br2(g)⇌2NOBr(g) ,Kp=28.4, at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 102 torr and that of Br2 is 134 torr . Part A What is the partial pressure of NOBr in this mixture? Express your answer in torrs to three significant figures.
The equilibrium constant, Kp, for the following reaction is 0.160 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 19.9 L container at 298K contains NOBr at a pressure of 0.297 atm and NO at a pressure of 0.251 atm, the equilibrium partial pressure of Br2 is ? atm.
for the reaction 2NOBr(g)---- 2NO(g)+Br2(g) the rate
of the reaction -2.3 mol NOBr/L/h when the initial NOBr
concentration was 6.2 mol NoBr/L. what is the rate constant of the
reaction.
Please help:)
52. For the reachon ZNO Brly) - 2Noig) + Brela) the rate of the reaction was -23 mol NoBrilh when the inihol NOBY Coventration was 2 mol NOBYL Wat is the rate constant of the reaction?