Find the 60th percentile of a standard normal distribution(3 decimal places) on StatCrunch
Using statCrunch,
P(Z < z) = 0.60
P(Z < 0.253) = 0.60
60th percentile = 0.253
Find the 60th percentile of a standard normal distribution(3 decimal places) on StatCrunch
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Suppose the variable x is represented by a standard normal distribution. What value of x is at the 60th percentile of the distribution? Equivalently, what is the value for which there is a probability of 0.60 that x will be less than that value? Please round your answer to the nearest hundredth.