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Find the 60th percentile of a standard normal distribution(3 decimal places) on StatCrunch

Find the 60th percentile of a standard normal distribution(3 decimal places) on StatCrunch


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Answer #1

Using statCrunch,

P(Z < z) = 0.60

P(Z < 0.253) = 0.60

60th percentile = 0.253

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