An elliptical hair that is 80µ by 120µ in minor and major diameters that is 10 cm long is extended to 10.07 cm by a weight of 25 grams. What is Young’s modulus in GPa?
Solution:
Diameter = 80 x 10^-6 m => radius = 40 x 10^-6 m
Young's modulus = stress/strain
=> Y = (FL/ALc)
Here;
Lc :change in length
L : initial length
hence;
Y = (0.025 x 9.81) x0.1 / pi x (40 x 10^-6)^2 x 0.0007
=> Y = 6.97 x 10^9 Pa
=> Y = 6.97 Gpa or 7 Gpa (approx.)
An elliptical hair that is 80µ by 120µ in minor and major diameters that is 10...
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