1 4 7 10 2 5 8 11 3 6 9 12 I want to print...
1 4 7 10
2 5 8 11
3 6 9 12
I want to print this matrix in c language.
How did this formula come out? （3 * j + i + 1);
#include <stdio.h>
int main()
{
int y[3][4];
int i, j;
for (i = 0; i < 3; i++)
{
for (j = 0; j < 4; j++)
printf("%d ", 3 * j + i + 1);
printf("\n");
}
return 0;
}
Homework Answers
i is for rows -- # of rows = 3
j is for columns -- # of cols = 4
Since indices start with 0, we are taking i+1 to get the the number in the row.
In each column, we have 3 numbers. So, we have 3 * j.
Debug to print output "2 3 5 6 8 11": #include <stdio.h> #include <stdlib.h> int main()...
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Could you do that in C language? Here is the code which we got #include <stdio.h>...
Could you do that in C language?
Here is the code which we got
#include <stdio.h>
#define MAX_SIZE 20
// function definitions
void displaySpiral(int matrix[][MAX_SIZE], int size);
void displayMatrix(int matrix[][MAX_SIZE], int size);
int takeInput(int inputMatrix[][MAX_SIZE]);
int main() {
int matrix[MAX_SIZE][MAX_SIZE];
int matrixSize = takeInput(matrix);
printf("Displaying the whole matrix:\n");
fflush(stdout);
displayMatrix(matrix, matrixSize);
printf("Now, displaying the matrix in a spiral way:\n");
fflush(stdout);
displaySpiral(matrix, matrixSize);
return 0;
}
// already implemented for you
int takeInput(int inputMatrix[][MAX_SIZE]) {
int size;
printf("What is the size...
3) (10 pts) For the purposes of this question, a permutation of size n is any...
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#include<stdio.h> int functionl (int x, int y); int main() int ij=2,k; for(i=1;i<=5; i++) k = function1(ij);...
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1 #include <stdio.h> 2 3 11 Remember this written by the 4 // "new guy down the hall". 5 6 pint main(int argc, char *argv[]) { 7 int a = 200; 8 int b = 300; 9 int c = 500; 10 if (a > 400) 11 b += 10; 12 else 13 if (c > 300) b += 50; 14 else b += 20; C += 10; 15 C += 100; 16 if (b > 800) 17 C +=...
Could you do that in C language?
Here is the code which we got
#include <stdio.h>
#define MAX_SIZE 20
// function definitions
void displaySpiral(int matrix[][MAX_SIZE], int size);
void displayMatrix(int matrix[][MAX_SIZE], int size);
int takeInput(int inputMatrix[][MAX_SIZE]);
int main() {
int matrix[MAX_SIZE][MAX_SIZE];
int matrixSize = takeInput(matrix);
printf("Displaying the whole matrix:\n");
fflush(stdout);
displayMatrix(matrix, matrixSize);
printf("Now, displaying the matrix in a spiral way:\n");
fflush(stdout);
displaySpiral(matrix, matrixSize);
return 0;
}
// already implemented for you
int takeInput(int inputMatrix[][MAX_SIZE]) {
int size;
printf("What is the size...
3) (10 pts) For the purposes of this question, a permutation of size n is any ordering of the integers 0, 1, 2, ..., n-1. We define a spaced-out permutation of size n to be a permutation such that two consecutive terms in the permutation differ by at least 2. For example, [0, 2, 4, 1, 3] is a spaced out permutation of size 5, and [5, 2, 4, 0, 3, 1] is a spaced out permutation of size 6,...
#include<stdio.h> int functionl (int x, int y); int main() int ij=2,k; for(i=1;i<=5; i++) k = function1(ij); printf("k=%d\n",k); return 0; int function] (int x, int y) int z; z=x*2+y; return z;
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