Question

For a second serial dilution, you will use the 6.00 ppm solution (that you just made in step a. above) to make the next, 3.60 ppm solution. How many mL of the 6.00 ppm solution must you use to make 25.00 mL of 3.60 ppm solution (round to the nearest mL)?

*C1V1 = C2V2*

Please show work.

The answer to step A was 15.0mL. Not sure if this is needed.

Answer 1

Given: 6 ppm solution. Using 6 ppm solution we have to prepare 25 mL of 3.60 ppm solution

C₁V₁ = C₂V₂

6 ppm X V₁ = 3.60 ppm X 25 mL