mass of gas [m]= 22.0 g
pressure [P] = 856 torr =[856/760] atm = 1.126 atm
temperature [T] = 25.0 +273.0 = 298 K
volume [V] = 3.00 L
gas constant R=0.0821 L.atm.K-1.mol-1
we know the ideal gas equation as PV = nRT where n=mass/molecular weight
substituting the values in ideal gas equation, we get
1.162*3.00 = [22g / molecular weight]*0.0821*298
or 3.486 = [22g / molecular weight] * 24.4658
or 3.486/24.4658 = 22g / molecular weight
or 0.1425 = 22g / molecular weight
or molecular weight = 22 g / 0.1425 = 154.386 g.mol-1
find the molecular weight of a gass mass = 22.0 g pressure = 856 torr temp...
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