What is the pH of a 3.3 x 10^-7 M NaOH solution? [_____________] = pH
Please write out all steps
NaOH dissociates in aqueous solution fully, as-
NaOH
Na+ + OH- .
So, 3.3×10-7 M NaOH dissociates to give 3.3×10-7 M OH- .
So, [OH-] = 3.3×10-7
In aqua solution solution : [H+] × [ OH- ] = 1×10-14
Hence, [H+] = 1×10-14/ [OH-]
So, [H+] = (1×10-14)/(3.3×10-7)
Or, [H+] = 3.03 × 10-8 .
We know, pH = -log[H+]
So, pH = - log (3.03×10-8)
Hence, pH = 7.52.
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