Ethylene glycol, used as a coolant in automative engines, has a specific heat capacity of 2.42 J/(g X k). Calculate q when 1.00 kg of ethylene glycol is cooled from 100 degrees celsius to zero degrees celsius.
Given:
m = 1000 g
C = 2.42 J/g.oC
Ti = 100 oC
Tf = 0 oC
use:
Q = m*C*(Tf-Ti)
Q = 1000.0*2.42*(0.0-100.0)
Q = -242000 J
Answer: -2.42*10^5 J
Ethylene glycol, used as a coolant in automative engines, has a specific heat capacity of 2.42...
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