Suppose a population is known to be normally distributed with a mean, μ, equal to 116...
Suppose a population is known to be normally distributed with a mean, μ, equal to 116 and a standard deviation, σ, equal to 14. Approximately what percent of the population would be between 102 and 130?
Homework Answers
Solution :
Given that ,
mean = 
= 116
standard deviation = 
= 14
P(102< x <130 ) = P[(102-116) /14 < (x - 
) / < (130-116) / 14)]
= P( -1< Z < 1)
= P(Z <1 ) - P(Z < -1)
Using z table
= 0.8413 -0.1587
=0.6826
=68.26%
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