The probability that a circuit board coming off an assembly line
needs rework is 0.1. Suppose that 10
boards are tested and all boards are independent of each other, and
let ? be the number of circuit boards
that need rework.
(a) Find ? ?!
(b) What is the probability that exactly 8 boards need rework?
X ~ Bin ( n , p)
Where n = 10 , p = 0.1
a)
E(X) = n p = 10 * 0.1 = 1
b)
Binomial probability distribution is
P(X) = nCx * px * ( 1 - p)n-x
So,
P(X = 8) = 10C8 * 0.18 * ( 1 - 0.1)2
= 0.0000
The probability that a circuit board coming off an assembly line needs rework is 0.1. Suppose...
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