how many cesium atoms could be placed end to end along the diameter of the penny?

Question

Question

Answer 1

Answer #1

Answer:

The diameter of the penny = 19.05 mm

= 19.05 x 10^-3 m

The atomic radius cesium atom = 0.267 nm

Therefore diameter of one cesium atom = 2 x 0.267 = 0.534 nm

= 0.534 x 10^-9 m

number of cesium atom that can be placed end to end along the diameter of the penny

= [diamter of the penny] / [diameter of one cesium atom]

= 19.05 x 10^-3 m / 0.534 x 10^-9 m

= 35.674157 x 10⁶ atoms.

= 3,56,74,157 atoms.

Answer 2

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