Question

If 18.1 mol of Ar gas occupies 111.5 L, how many mL would occupy 59.3 mol occupy under the same temperature and pressure? Record your answer in scientific notation using 3 significant figures.

Answer 1

Answer

365301ml

Explanation

Ideal gas equation is

PV = nRT

V = nRT/P

Temperature and pressure is constant ,so

V = n k

V1 = n1 k

V2 = n2 k

V1/V2 = n1/n2

V1 = 111.5L

V2 = ?

n1 = 18.1mol

n2 = 59.3mol

V2 = V1×n2/n1

= 111.5L × 59.3mol /18.1mol

= 365.301L

= 365301ml