Question

what is the molarity of an HCL solution 28.6ml of a .175 m NaOH solution is needed to titrate a 15.0 ml sample of HCL solution

HCL(aq)+ NaOH(aq) -> NaCL(s) + H2O (l)

Answer 1

We know that number of moles of solute = Molarity of solution x Volume of solution (L)

So number of moles of NaOH=Molarity of NaOH x Volume of NaOH (L)

=0.175 M x 28.6 ml/1000 ml/L=5.005 x 10^-3 mol

As per the given balanced chemical equation

1 mol NaOH reacts with 1 mol HCl

So 5.005 x 10^-3 NaOH reacts with 5.005 x 10^-3 mol HCl

So molarity of HCl solution=number of moles of HCl/volume of HCl solution (L)

=5.005 x 10^-3 mol/15.0 ml/1000 ml/L=0.334 M

So molarity of HCl solution is 0.334 M