Question

Re: Titration with NaOH for Vitamin C

Calculate from your titration results the moles of acidic protons in the tablet neutralized by the NaOH.
0.0500M of NaOH
volume of NaOH added = 26.80 mL
1 0
Add a comment Improve this question Transcribed image text
Answer #1

Moles of acidic protons neutralised = moles of NaOH

= M x V

= 0.05 x 26.8 x 10-3

= 1.34 x 10-3 moles

answered by: chemistry-master
Add a comment
Know the answer?
Add Answer to:
Re: Titration with NaOH for Vitamin C
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Titration with NaOH for Tang: 1. Calculate from your titration results the moles of acidic protons...

    Titration with NaOH for Tang: 1. Calculate from your titration results the moles of acidic protons in your total mass of Tang titrated. 2. Convert your answer to moles of acidic protons per gram of Tang titrated. mass of tang = 5.762g volume of NaOH added = 38.98 ml molarity of NaOH = 0.102M

  • need to calculate tritation values correction trial 2 final volume of NaOH is 30.2ml EXPERIMENT 11 LABORATORY...

    need to calculate tritation values correction trial 2 final volume of NaOH is 30.2ml EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Rugbu Cost of antacid 4.5 ¢ per tablet Average mass of tablet_1-30129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) .1006 Data Trial 1 Trial 2 Mass of sample (g) 0-104 Initial volume of HCl (mL 10.116 49.1 12101 4601 24.1 Final volume of HCl (mL) Initial volume of NaOH (mL 49.6 48.2 Final volume...

  • Calculate the Amount of HCl Neutralized by Titration (mol) Parts 1 & 2, Standardization of NaOH and HC Record the mclarities from standardization or from reagent bottles of the HCl and the NaOH....

    Calculate the Amount of HCl Neutralized by Titration (mol) Parts 1 & 2, Standardization of NaOH and HC Record the mclarities from standardization or from reagent bottles of the HCl and the NaOH. molarity of HCI1.0780 molarity of NaOH 4851 Your value is acceptable. M Your value is acceptable. M Part 3. Determination of the Amount of Acid Neutralized by an Antacid Tablet Record the data from your titration in Table 1. (Enter NONE in any unused answer blanks.) Table...

  • need calculation for this experiment EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid —...

    need calculation for this experiment EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid — Rugby 4. 5 € per tablet Average mass of tablet_1-30129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 2.1006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 49.1 Initial volume of HCI (mL 0-104 46.1 24-1 Final volume of HCI (mL) 21.) Initial volume of NaOH (mL 49.6 49.1 Final volume of NaOH (mL) 34.2 344 31-1 140...

  • need calculation for this tritation values please EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of...

    need calculation for this tritation values please EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid Rugby 4, 5 per tablet Average mass of tablet 130129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 01006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 Initial volume of HCl (mL 0.9 0-104 3.9 22-2 Final volume of HCI (mL) Initial volume of NaOH (mL 28 0.4 34.2 7-8 Final volume of NaOH (mL) 30:2 140...

  • An unknown acid is titrated with a strong base (NaOH) to produce the above titration curve....

    An unknown acid is titrated with a strong base (NaOH) to produce the above titration curve. Key points on this graph reveal important information about the substance and the solution created with it. What volume of NaOH is needed to reach the equivalence point (the point where you added equal moles of NaOH to the acid)?    Select one of the following : ["10 mL", "5 mL", "20 mL", "30 mL", "40 mL", "25 mL", "15 mL", "35 mL"]      ...

  • Lab 11 Acid-Base Titration Part 2: Data Table for H2SO, titration HSO4 (aq) + 2 NaOH(aq)...

    Lab 11 Acid-Base Titration Part 2: Data Table for H2SO, titration HSO4 (aq) + 2 NaOH(aq) Table 3. Data + Sulfuric Acid Volume Na2SO. (aq) + 2 H2O(1) used - 10.00 m2 - Trial 1 Trial 2 Trial 3 (optional) H2SO4 used (A, B, C) Actual volume of H2SO4 (mL.) Initial buret reading (mL) Final buret reading (mL) 2.52mL 1.50mL 19.40mL 14.6ImL 31.42 m2 19.50ml Table 4. Results Calculations Trial 1 Trial 2 Trial 3 (optional) Volume of NaOH nitrated...

  • Standardization of NaOH: Acid Base Titration Objective: In this lab, you will accurately determine the concentration...

    Standardization of NaOH: Acid Base Titration Objective: In this lab, you will accurately determine the concentration of a solution of sodium hydroxide (NaOH) using a 0.500M potassium hydrogen phthalate (KHP) standard solution. Background: Acid–Base Titrations When an acid reacts with a base, a neutralization reaction occurs. The H+ ions from the acid and the HO– ions from the base combine to form water and are therefore neutralized. The other product of reaction is a salt. For example, hydrochloric acid reacts...

  • A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and...

    A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NAOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H806 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 14.47 Concentration of NaOH in mol/L, 0.1964 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg). Answer:

  • 4. A student analyzed an antacid tablet from a bottle of 48 tablets purchased at a...

    4. A student analyzed an antacid tablet from a bottle of 48 tablets purchased at a discount store for $1.00. The mass of the tablet was 1.462g. After adding 25.00mL of 0.8000/M HCl solution to the tablet, the student back-titrated the excess HCI with 3.52 mL of 1.019M NaOH solution. (a) Calculate the number of moles of HCI added to the tablet (b) Calculate the number of moles of NaOH required for the back-titration (c) Calculate the number of moles...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT