A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and...
1. A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titrated with the NaOH solution until a light pink color appeared using phenolpthalein indicator. Using the volume of NaOH required to neutralize KHP and the number of moles of KHP titrated, the concentration of the NaOH solution was calculated. Molecular formula of Potassium hydrogen phthalate: HKC8H404 Mass of KHP used for standardization (g) 0.5100 Volume of NaOH required to neutralize...
Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data: A 100 mg sample of a crushed Vitamin C tablet was dissolved in 40 mL of H2SO4 and 20 mL of water. Two grams of KI and 35 mL of 0.0107 M KIO3 solution was added, and the mixture titrated to a starch endpoint. The titration required 12 mL of 0.0790 M thiosulfate solution.
Ascorbic acid, vitamin C, is a water-soluble vitamin. A solution that contains 80.5g ascorbic acid, C6H806 dissolved in 210g of water has a density of 1.22g/mL at 55C. With this information, answer the exercises of the 15-18. calculate % per mass of ascorbic acid, vitamin C calculate the molar fraction of ascorbic acid, vitamin C calculate the molality of ascorbic acid, vitamin C Calculate the molarity of ascorbic acid, vitamin C
A tablet containing some Vit C (ascorbic acid) was dissolved in water then titrated with 24.88 ml of 0.1085 M NaOH. What is the w/w% of Vit C in the tablet if the tablet weighed 0.6672 g? (use Vit C = 176.0 g/mol) NaOH + Vit C rightarrow sodium ascorbate + H_2O
Ascorbic acid (vitamin C, MM 176.124 g/mol)) can be determined using an iodometric back titration. A vitamin C tablet was dissolved in 60 mL of 0.3 M H2S04. To the dissolved tablet, 2 g of KI and 50.00 mL of 0.0105 M KIO3 were added, resulting in the formation of a dark orange solution indicating the presence of 13-. The resulting solution was titrated with 0.0685 M S2032- until the starch indicator turned purple. If the end point was observed...
Vitamin C (ascorbic acid) from foods can be measured by titration with I3-If 29.41 mL of I3- solution are required to react with 0.1970 g of pure ascorbic acid, what is the molarity of the I3- solution? A vitamin C tablet containing ascorbic acid plus inert binder was ground to a powder, and 0.4242 g was titrated by 31.63 mL of I3-. How many moles of ascorbic acid are present in the 0.4242 g sample? Find the weight percent of...
Questions: 1. 495 mg of dried KHP is dissolved in 35 mL of distilled water and titrated with potassium hydroxide (KOH). If it took 22.02 mL of KOH to reach the endpoint, determine the concentration of KOH. Show calculations. If you forgot to dry the above KHP sample and it was later determined to contain 5.00 % water by weight, what would be the actual concentration of the KOH, taking into account the water content? Show calculations. 2. If you...
The student dissolved 2.050 grams of acid in 50 mL of distilled water. He then titrated the unknown acid with a standardized NaOH solution. Unfortunately, the student over shot the end point and had to back titrate the solution with 2.17 mL of 0.98861 M HCl. Once the final end point was determined, the student had added a total of 29.15 mL of a 1.0324 M NaOH solution. A) How many moles of OH- were used to reach the end...
The student dissolved 2.050 grams of acid in 50 mL of distilled water. He then titrated the unknown acid with a standardized NaOH solution. Unfortunately, the student over shot the end point and had to back titrate the solution with 2.17 mL of 0.98861 M HCl. Once the final end point was determined, the student had added a total of 29.15 mL of a 1.0324 M NaOH solution. A) How many moles of OH- were used to reach the end...
A student prepared a base solution using 7 mL of 6M NaOH diluted with distilled water to a final volume of approximately 400 mL. The student titrated a standardized solution of HCl to determine the exact concentration of the prepared base solution. In the first titration, she found that it took 22.47 mL of the base solution to neutralize 20.00 mL of a 0.98861 M HCl solution. In the second titration, she found that it took 20.12 mL of the...