Question

a person throws a ball upward into the air with an initial velocity of 15 m/s calculate a)how high it goes

a person throws a ball upward into the air with an initial velocity of 15 m/s calculate
a)how high it goes?
b)how long the ball is in the air before it comes back ?
c)how much time it takes for the ball to reach the maximum height?
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Answer #1
h = 15t - 4.9t^2 = 4.9t(3.06-t)

(c) max height is reached at t = 15/9.8

(b) h=0 when t=0 or 3.06

(a) calculate h using (a)
answered by: kieron
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