Question

Ba Example 2-16 Ball thrown upward A woman throws a ball upward into the air with an initial velocity of 15.0 m/s. Calculate: (a) How high it goes (b) The time for the ball to reach its maximum height Ignore air resistance. 2-7 Freely Falling Objects Example 2-16 Ball thrown upward A woman throws a ball upward into the air with an initial velocity of 15.0 m/s. Calculate: (c) How long the ball is in the air before she catches it (d) Velocity of the ball when she catches it. Ignore air resistance. 2-7 Freely Falling Objects Example 2-16 Ball thrown upward A woman throws a ball upward into the air with an initial velocity of 15.0 m/s. Calculate: (e) What time t the ball passes a point 8.00m above the woman's hand

Answer 1

Initial velocity = u = 15 m/s (a) Maximum Height Let it be 'H' We know that at maximum height, final velocity is zero that is V = 0 using equation V^2 - u^2 = 2as 0 - (15)^2 = 2 times (-9.8) times H [because a = -g] therefore H = 225/2 times 9.8 = 11.48 m therefore maximum height = H = 11.48 m (b) Now, Time taken = T = ? We know that V = u + at \r\n In the motion from A to B V = 0, u = 15 m/s, a = -g therefore 0 = 15 + (-g)T therefore T = 15/9.8 = 1.53 s T = 1.53 s (c) Time of flight = time for which the ball is in the air t = 2 times T = 2 times 1.53 = 3.06 s (as time taken for going up and coming down is same) \r\n if we consider motion from