How many moles of Mg3P2(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol...

Question

Question

How many moles of Mg3P2(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P4(s)? ____ Mg(s) + ____ P4(s) ____ Mg3P2(s)

Answer 1

Answer #1

the balanced chemical equation for the reaction is

6Mg(s) + 1P4(s) --> 2 Mg3P2(s)

∴ for every 1 mole of P4 we get 2 moles of Mg3P2

∴ for .020 moles of P4 we ge 0.02 *2 = 0.04 moles of Mg3P4

Answer 2

Answer #2

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Answer 3

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