Part A
Answer
12mol
Explanation
N2(g) + 3H2(g) -------> 2NH3(g)
stoichiometrically , 3moles o H2 produces 2moles of NH3
So,
Number of moles of NH3 produced by 18moles of H2 = (2/3)×18mol = 12mol
Part B
Answer
128.82g
Explanation
N2(g) + 3H2(g) ------> 2NH3(g)
stoichiometrically, 1mole of N2 produce 2moles of NH3
Number of moles of NH3 produced by 3.78moles of N2 = 3.78mol × 2 = 7.56mol
mass = number of moles × molar mass
mass of NH3 can be produced = 7.56mol × 17.04g/mol= 128.82g
Part A able How many moles of NH3 can be produced from 18.0 mol of H2...
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Learning Goal: To understand how to use stoichiometry to convert between quantities of reactants and products in chemical equations. Stoichiometry describes the quantitative relationships among the reactants and products of a balanced reaction by directly comparing mole ratios. Stoichiometry can be used to convert mass, number of moles, or number of particles between products and reactants, as shown in the flowchart displayed in the figure. (Figure 1)How many grams of NH3 can be produced from 4.74 mol of N2 and excess H2. Express...
3H2(g)+N2(g)→2NH3(g) a. How many moles of NH3 can be produced from 13.5 mol of H2 and excess N2? b. How many grams of NH3 can be produced from 4.90 mol of N2 and excess H2. c. How many grams of H2 are needed to produce 12.74 g of NH3? d. How many molecules (not moles) of NH3 are produced from 1.05×10−4 g of H2?
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Part C How many grams of H, are needed to produce 13.93 g of NH3? Express your answer numerically in grams. View Available Hint(s) IVO AQ * O 2 ? g H2 Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Part D How many molecules (not moles) of NH3 are produced from 7.02x10-4 g of H2? Express your answer numerically as the number of molecules. ► View Available Hint(s) VO AQ R o 2 ? |