Question

Part C How many grams of H, are needed to produce 13.93 g of NH3? Express your answer numerically in grams. View Available Hint(s) IVO AQ * O 2 ? g H2 Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Part D How many molecules (not moles) of NH3 are produced from 7.02x10-4 g of H2? Express your answer numerically as the number of molecules. ► View Available Hint(s) VO AQ R o 2 ? |

Answer 1

The answer of the above 2 question is as follows

part-c Ammonia CNH) can be produced 7000 N and He by the following reaction N₂ + 3H₂2NH₂ Given mass of NH₃ = 13.939 Molar mass of NH₃ = 17 glmole. : Number of moles of NH3 - Given mass Molar mass = 13.939 17 gimole = 0.819 more From the balanced chemical It equation that coas clear c of NH₃ is = 3 moles of roduced from Ho 10 of NH3 = 3 more of - 3 a moles of NH₃ is Inic prodrom ã th 1 more of NHO is produced بالع xo.819 mole 0.819 mole of NH3 is produced is por from

: 0.819 mole of NH₃ - 3x0.819 is produced from a mole H2 - 1.2285 mole H2 mass mass of 1 mole of H₂ - 29 of 1.2285 mole of Hy = \-2285x2g 2 = 2.4579 . 13.93 g of NH, is produced I from 2.457 g H₂ part-D Given mass of H₂ = 7.02 x 104g Nolar mass of H = a glmole! No.of moles of H₂ - Given mass Trolar mass - 7.02x10g L agimore = 3.51810 mole

mole 3 moles of H₂ give = an NH3 I more of Hy give = a mole of 3.5010" mole H give = 2x3.5) X10 3 more NH3. = 0.66 X3.5)xey = 2.34 X10-Y mole NH₃ As per Avogadoo's law 1 more of NH contains - 6.02 x 1023 no. of NH₃ molecule 2.34 X10" mole of Nito contains = 6.02810²3 x 2.34x104 = 6.02x2.34 x 1019 - 14.08 x 1019 - 7.408 x 1020 no ..).408x10 number of molecules OYNH, no of NH₃ molecule. 20