Question

Molar Mass of Volatile liquid

A volatile liquid is vaporizedat a temperature of 89.3ºC in a container with a volume of141.3 mL. At the time of the experiment, the room pressure wasfound to be755.5 mmHg. If the mass of the vapor was found to be0.3145 g, what is the molar mass of the volatileliquid?


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Answer #1
Given that
Pressure, P = 755.5 mmHg= 0.994 atmVolume, V = 141.3 mL= 0.1413 LTemperature, T = 89.3 0C=362.3KMass of gas = 0.3145 gAccording to ideal gas equationPV = nRT= (mass/molarmass) RT∴ Molar mass = mass * RT /PV=(0.3145 g )(0.0821 Latm/K.mol)(362.3 K)/(0.994 atm)(0.1413L)=66.6 g/mol
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