Stress, elongation strain, and Young's modulus of a wire
1. what is the stress on the wire?
2. what is the elongation strain on the wire?
3. what is the Young's modulus of the wire?
Thanks so much.
Homework Answers
E=tensile stress/tensile strain
tensile stress = Force/Cross-sectional area
tensile strain = change in length / original length
tensile stress = 10^2N/1x10^-6m
tensile stress = 10^8
tensile strain = 1.0m-1.005m/1.0m
tensile strain = .005/1.0= 5x10^-3
ans= 10^8/5x10^-3
ans =0.2x10^11
A 5 ´ 102-N object is hung from the end of a wire of cross-sectional area 0.01 cm2. The wire stretches from its original length of 200 cm to 200.5 cm
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The Young's modulus for a femur is 9 times 10^9 N/m^2, the cross sectional area is 8 cm^2 and initial length is 43 cm. What is the change in length if half of your weight is placed on the femur? (standing up) Find: Given: Concept(s): Solution:
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Young's modulus equation is E = tensile stress/tensile strain =
(FL) / (A * change in L), where F is the applied force, L is the
initial length, A is the square area, and E is Young's modulus in
Pascals (Pa).
Figure P4.37 shows a hand crank with static vertical load applied to the handle. (a) Copy the drawing and mark on it the location of highest bending stress. Make a three-dimensional Mohr circle representation of the stresses at this...
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