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Determine the equilibrium constant (Keq) at 25°C for the reaction?Cl2(g) + 2Br- (aq) -> Cl- (aq) + Br2(l)A. 1.5 × 10-10 B. 6.3 × 109 C. 1.3 × 1041 D. 8.1 × 104 E. 9.8
5. Determine the equilibrium constant (Keg) at 25°C for the reaction Cla(g)+2Br (aq) 늑 2C1-(aq) + Br2(1) A) 1.5×10-10 B) 6.3×109 C) 1.3×1041 D) 8.1 x 104 E) 9.8
Calculate the equilibrium constant for each of the reactions at 25 ∘C. Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction E∘(V) Pb2+(aq)+2e− →Pb(s) -0.13 Zn2+(aq)+2e− →Zn(s) -0.76 Br2(l)+2e− →2Br−(aq) 1.09 Cl2(g)+2e− →2Cl−(aq) 1.36 MnO2(s)+4H+(aq)+2e− →Mn2+(aq)+2H2O(l) 1.21 Pb2+(aq)+2e− →Pb(s) -0.13 Br2(l)+2Cl−(aq)→2Br−(aq)+Cl2(g) Express your answer using two significant figures.
20 Calculate the equilibrium constant, Keq, at 25 egrees C for the reaction: 2Br-(aq) + 12(5) - Br2(1) + 21-(aq). (Eored.cathode=0.54V and Eored, anode=1.CJV) S (4 Puan) 1.11x10-16 1.62x10-18 1.52x10-16 1.25x10-18 2.25x10-16
2 Determine the equilibrium constant, Keq, at 25°C for the reaction 2Br (aq) +12/5) = Br261 +21+ (aq). Multiple Choice 17 x 1054 5.7 x 10-55 57 10-19 18.30 19 1018 M
Calculate the equilibrium constant for each of the reactions at 25∘C. Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction E∘(V) Fe3+(aq)+3e− →Fe(s) -0.036 Sn2+(aq)+2e− →Sn(s) -0.14 Ni2+(aq)+2e− →Ni(s) -0.23 O2(g)+2H2O(l)+4e− →4OH−(aq) 0.40 Br2(l)+2e− →2Br− 1.09 I2(s)+2e− →2I− 0.54 A) 2Fe3+(aq)+3Sn(s)→2Fe(s)+3Sn2+(aq) (answers are not 4.1x10^5, 3.3x10^3, 2.7x10^10, or 2.6x10^10) B) O2(g)+2H2O(l)+2Ni(s)→4OH−(aq)+2Ni2+(aq) C) Br2(l)+2I−(aq)→2Br−(aq)+I2(s) (answer is not 1.7x10^18)
Calculate the equilibrium constant K for the reactions at 298 K. a) Br2(g) + 2Cl-(aq) ---> 2Br-(aq) + Cl2(g) b) A Galvanic Cell with the SHE and Fe+2/Fe(s)
Calculate the equilibrium constant for each of the reactions at 25∘C∘C. Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction Cl2(g)+2e ---> 2CI- 1.36 I2(s)+2e --> 2I- 0.54 Part A Cl2(g)+2I−(aq)→2Cl−(aq)+I2(s) K= ?
Question 14 a. Write the equilibrium constant expression (Keq) for the reaction below. 3H2(g) + 1 N2(8) 2NH3(g) b. When is a reaction at equilibrium? Question 15 Solve (Show all your work !!!!!!!) How many quarts in 6.3 liters? Question 16 5 pts Solve (Show all your work!!!!!) How many kilograms (Kg) are there in 3.5 x 104 decigrams (dg)? 12pt v Paragraph v B I DI v T²v ...
Exercise 18.67: Problems by Topic - Cell Potential, Free Energy, and the Equilibrium Constant Calculate the equilibrium constant for each of the reactions at 25 ∘C. Part A Pb2+(aq)+Mg(s)→Pb(s)+Mg2+(aq) Express your answer using one significant figure. K = 5×1075 SubmitMy AnswersGive Up All attempts used; correct answer displayed Part B Br2(l)+2Cl−(aq)→2Br−(aq)+Cl2(g) Express your answer using one significant figure. K = 6•10−10 SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part C MnO2(s)+4H+(aq)+Cu(s)→Mn2+(aq)+2H2O(l)+Cu2+(aq) Express your answer using one significant figure....