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In the following figure = 20.0 and = 52.7. The coefficient of kinetic friction between the block...

In the following figure = 20.0 and = 52.7. The coefficient of kinetic friction between the block and the incline is = 0.40
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Answer #1
"constant speed" tells us that the applied force just offsets friction + weight of the block along the plane.
T = arctan(30/40) = 36.9º
Component of weight parallel to plane Fp = mg·sinT = 1400kg·9.8m/s²·sin39.6 = 8232 N
Friction force Ff = µmg·cosT = 0.4·1400kg·9.8m/s²·cos39.6 = 4390 N
Therefore the tension in the cable is 12622 N
Power = force · distance / time = 12622N · 1.35m/s = 17040 W
answered by: Ashton
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