using conservation of energy
qV = .5mv^2
q = charge on proton = 1.6 x 10^-19 C
.5mv^2 = 1.6 x 10^-13
so
we get v = 1.3843 x 10^7 m/s
Charge q= 1.6 * 10 ^ -19 C
Mass m = 1.67 * 10 ^ -27 kg
Potential difference V = 1 Mv = 10 ^ 6 V
Final speed v = √ [ 2Vq / m]
Plug the values we get v = 1.384 * 10^ 7 m / s
In two significant figures v = 1.4 * 10 ^ 7 m / s
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