The illumination of an object by a light source is directly proportional to the strength of the source and inversely proportional to the square of the distance from the source
Homework Answers
ks/x^2 = k(4s)/(11-x)^2
or
4x^2 = (11-x)^2
4x^2 = 121 - 22x + x^2
3x^2 + 22x -121 = 0
(x+11)(3x-11) = 0
BRIGHT_____x__WEAK
8'4" -- 3'8"
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The illumination of an object by a light source is directly proportional to the strength of the source and inversely proportional to the square of the distance from the source
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The illumination of an object by a light source is directly proportional to the strength of the source and inversely proportional to the square of the distance from the source. If two light sources, one three times as strong as the other, are placed 10 ft apart, how far away from the stronger light source should an object be placed on the line between the two sources so as to receive the least illumination? (Round your answer to two decimal...
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The illumination of an object by a light source is directly proportional to the strength of the source and inversely proportional to the square of the distance from the source. If two light sources, one three times as strong as the other, are placed 10 ft apart, how far away from the stronger light source should an object be placed on the line between the two sources so as to receive the least illumination? (Round your answer to two decimal...
The intensity of a light source at a distance is directly
proportional to the strength of the source and inversely
proportional to the square of the distance from the source. Two
light sources, one five times as strong as the other, are 9 m
apart. At what point on the line segment joining the sources is the
intensity the weakest? Write an equation representing the
intensity, I, at a distance, x, from the weaker lightbulb, and with
k as the...
12) The illumination, I, produced by a light source varies inversely as the square of the distance, D from the light source. Suppose the illumination, I, was 88 footcandles when the distance, D, from the light source was 5 feet. Find the illumination, I, produced when the distance, D, is 4 feet from the same source. Round answer to the nearest tenth of a footcandle.
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streamlines as indicated by the dashed arrows, is placed a distance
L away from a vertical wall (occupying the yz-plane), at point S
(x=L,y= 0). To compute the flow field in the presence of the wall,
the method of images can be employed: A second source of strength m
is placed a distance L from the wall on the other side, at S′
(x=−L,y= 0). The combined flow field of...
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