Question

5 The intensity of light, 1, from a light source is inversely proportional to the square of the distance, d from the light source. (a) If the intensity of light is 4 watts per square meter at a distance of 6 meters from the light source, create a function representing the relationship. (b) Find the intensity of light at a distance of 8 meters from the light source. (c) At what distance would the light quadruple in intensity? 6. Find a power function the goes through the two points (1, 2) and (8, 128).

Answer 1

Ans Given : I= light of the intensity ; da The distance from the light source. a) The intensity of the light I)= 4 watt per square metse Distance from the light (d) = 6 meter. /:k= It the constant value) So, put the values nak k= 4x(6)? ka) 1440 b) 1. Distance So, from the Isk light (1) = 8 meter. [":k value in pard a) d? sta 144 of stay (832 8X8 7 2 2 2 2.95 wat per square meter.