Question

the work-energy theorem

Learning Goal: To understand the meaning andpossible applications of the work-energy theorem.

In this problem, you will use your prior knowledge to derive one ofthe most important relationships in mechanics: the work-energytheorem. We will start with aspecial case: a particle of massmmoving in the x directionat constant accelerationa.During a certain interval of time, theparticle accelerates fromv_initial to v_final, undergoing displacement sgiven by s=x_{rm final}-x_{rm initial}.part A.Find the acceleration a of the particle.Express the acceleration in terms ofv_initial,v_final, and s.part BFind the net force F acting on the particle.Express your answer in terms ofmand a.part cFind the net work Wdone on the particle by the externalforces during the particle'smotion.Express your answer in terms ofFand s.part DSubstitute for Ffrom Part B in the expression forwork from Part C. Then substitutefor afrom therelation in Part A. This will yield an expression for thenet work Wdone on the particle by the external forces during the particle'smotion in terms of mass and the initial and final velocities.Givean expression for the work Win terms of thosequantities.Express your answer in terms ofm,v_initial, and v_final.part EFind the net work Wdone on the particle by theexternal forces during the motion ofthe particle in terms of the initial and final kineticenergies.Express your answer in terms ofK_initial and K_final.part FEvaluate the integral W=int_{v_{rm initial}}^{v_{rm final}}m v,dv.Express your answer in terms ofm,v_initial, and v_final.part GA particle moving in the x directionis being acted upon by a net force F(x)=Cx^2, for some constant C.The particle moves from x_{rm initial}=L to x_{rm final}=3L. What is DeltaK, the change in kinetic energy of the particleduring thattime?Express your answer in terms ofCandL.
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Answer #1
a)accelerationa =( v_final2 -v_initial2 )/ 2Sb)net force isF =m ac) work doneW = F .Sd) workW = (1/2)m[ v_final2 - v_initial2]e) workW = K_final- K_initialf) W=int_{v_{rm initial}}^{v_{rm final}}m v,dvW = m W = m [ V2final -V2initial ] /2g)The change in KE is= (C /3) [9L3 - L3 ]= 8CL3 /3
answered by: Karl2472

> g) the answer is (26CL^3)/3

Tammy Chu Sun, Oct 31, 2021 9:06 PM

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