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8.5 mL of a sample of sea water solution was added to a 44.317 g evaporating dish. The combination weighed 52.987 g. After eaporation the dish and contents weighed44.599 g.

a.) What was the mass percent of dissolved solids in the sea water?

b.) The actual solution chloride content in the sea water was 2.69%. If it had been assumed that the dissolved solid(s) consisted only of sodium chloride, whatpercentage error would have resulted? [Caution: the answer is not 0.56%]? The numbers included here are for a typical sea water sample. In addition to NaCl, typicalsea water contains about 0.56% by mass of compounds (primarily chlorides) of magnesium, calcium and potassium.
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Answer #1
mass of sea water added = 52.987 - 44.317 =8.67 g
after evaporation, solids = 44.599 - 44.317 = 0.282 g

mass % of dissolved solids = 0.282 / 8.67 * 100 = 3.25 %
answered by: lacour
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