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Current Loop I

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A square loop of wire is rotating around its vertical axis in a magnetic field of strength B = 0.06 T as shown in View A. The angular frequency of rotation isomega = 50 rad/s and the loop has a resistance of R = 5 ohm . The length of one side of the square loop is W = 0.05 m. At the instant of timewhen the normal to the loop makes an angle of theta = 30degrees with respect to the B field, as shown in View B where 'N' represents the normal,calculate the current flowing in the loop. Note: View A would be the side view if theta = 90degrees or 270degrees.

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Answer #2

v=rω
v = W/2ω
=0.05/2x50

=1.25 m rad./s

e = 2BWvsin 30°

=2x0.06x0.05x1.25sin30

I=e/R

=0.00075 A


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