1. A square loop of wire with one side of a and resistance R is placed in a uniform magnetic field of strength B. The field vanishes and results an induced current I in the loop.
( a) a) What is the rate of change of magnetic flux 
in terms of I and R?
(b) Magnetic field B (on the picture above) was equal to 0.5 T before it vanished. If the duration of switch is 0.15 sec and the side of the square wire a = 0.3 m, what is the average induced emf in the loop?
(c) What is the induced current in the loop if resistance of the wire R = 75 Ohm?
Homework Answers
a) induced voltage = IR
d phi/dt = IR
b) V = dphi/dt
= 0.3*0.3*0.5/0.15
= 0.3 V
c) current I = V/R
= 0.3/75
= 0.004 A
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